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2 years ago

The keypad on Sam’s cell phone is shown at right. As you can see,

1 answer:

3 0

To complete the table we must carefully observe the keypad, we will notice that each number is equivalent to 3 letters of the alphabet except the numbers 7 and 9 which have 4 letters each.

<h3>How does the keypad work?</h3>

Previously, cell phone keypad had a different layout than today. The numbers were related to the letters of the alphabet and the number key was pressed according to the letters that were related.

For example, if you wanted to type the letter B, you would have to press the number 2 key twice.

The relationship of numbers and letters was distributed as follows:

It had no letters.
A, B and C.
D, E and F.
G, H and I.
J, K and L.
M, N and O.
P, Q, R and S.
T, U and V.
W, X, Y, and Z.

According to the above, the table would be completed as follows.

Note: This question is incomplete because there is some missing information. Here is the missing information:

1. Complete this table to show the relation from letter to number.

Learn more about keypad in: brainly.com/question/1156254

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A rectangle has a width of six units and the length of 2X +8 units. If the area is 108 units squared, what is the value of X?

elena-s [515]

Width of rectangle = 6 units

Length of rectangle = 2X+8 units

Area = 108 units square

Area = length * width

$108=6(2x+8)$

$108=12x+48$

$12x=60$

$x=5$ units

5 0

3 years ago

Which volume could belong to a cube with a side length that is an integer? Recall the formula Cube volume = s cubed. 18 cubic in

irina1246 [14]

We have been given 4 choices. We are asked to choose the volume that could belong to a cube with a side length that is an integer.

We know that volume of a cube is cube of each side length.

To solve our given problem, we will take cube root of each given value. The cube root of which value will be an integer that will be our correct choice.

A. $s^3=18$

$\sqrt[3]{s^3}=\sqrt[3]{18}$

$s=2.62074$

Since cube root of 18 is not an integer, therefore, 18 is not a correct choice.

B. $s^3=36$

$\sqrt[3]{s^3}=\sqrt[3]{36}$

$s=3.301927$

Since cube root of 36 is not an integer, therefore, 36 is not a correct choice.

C. $s^3=64$

$\sqrt[3]{s^3}=\sqrt[3]{64}$

$s=4$

Since cube root of 64 is 4 and 4 is an integer, therefore, 64 is the correct choice.

D. $s^3=100$

$\sqrt[3]{s^3}=\sqrt[3]{100}$

$s=4.641588$

Since cube root of 100 is not an integer, therefore, 100 is not a correct choice.

5 0

3 years ago

Read 2 more answers

What is completely factored form or this expression?

sweet-ann [11.9K]

<h2><u>Answer</u><u> </u>:)</h2>

$\sf{y^{2}-12y+32 }$

$\sf{y^{2}-(8+4)y+32 }$

$\sf{y^{2}-8y-4y+32 }$

$\sf{ y(y-8)-4(y-8) }$

$\sf{(y-8)(y-4) }$

$\sf{(y-4)(y-8) }$

$\\\\\\$

<h3><u>Therefore</u><u> </u></h3>

$\sf{option~ B~ is ~correct }$

$\sf{ }$ $\sf{ }$ $\sf{ }$

6 0

3 years ago

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A psychologist collects data on the time, w, in minutes, people walk each day and their scores, t ,on a stress test. The scores

photoshop1234 [79]

<span>C. The people in the study walked an average of 48.1 minutes each day.
</span>

8 0

3 years ago

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F(x) = x2 – 3x – 2 is shifted 4 units left. The result is g(x). What is g(x)?

Ray Of Light [21]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now... your expression is not in vertex form, that's ok... to do a horizontal shift to the left by 4 units, we can simply, add the C and B component to the "x" variable, C=4, B =1, that way the horizontal shift of C/B or 4/1 is just +4, giving us a horizontal shift to the left

$\bf f(x)=x^2-3x-2\impliedby \textit{let's change that for }f(1x+4)
\\\\\\
f(1x+4)=(1x+4)^2-3(1x+4)-2
\\\\\\
f(x+4)=x^2+8x+16-3x-12-2
\\\\\\
f(x+4)=x^2-5x+2\impliedby g(x)$

8 0

3 years ago

Read 2 more answers