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strojnjashka [21]

3 years ago

9

Solve 3x-4=√(2x^2-2x+2)

1 answer:

DiKsa [7]3 years ago

8 0

Answer:

Step-by-step explanation:

Begin the solution by squaring both sides of the given equation. We get:

(3x - 4)^2 = 2x^2 - 2x + 2, or:

9x^2 - 24x + 16 = 2x ^2 - 2x + 2

Combining like terms results in:

7x^2 - 22x + 14 = 0

and the coefficients are a = 7, b = -22, c = 14, so that the discriminant of the quadratic formula, b^2 - 4ac becomes (-22)^2 - 4(7)(14) = 92

According to the quadratic formula, the solutions are

-b ± √discriminant -(-22) ± √92 22 ± √92

x = ------------------------------- = ----------------------- = ------------------------

2a 14 14

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Arrange the entries of matrix A in increasing order of their cofactors values

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$Ac_{33}=7\times 4- -7\times 5$

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$Ac_{33}=63$

Therefore in increasing order, we have;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

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