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2 years ago

Over which interval does f(t) have positive average rate of change

Mathematics

2 answers:

iren [92.7K]2 years ago

8 0

Answer: {2,4}

Step-by-step explanation: Khan Academy

Verdich [7]2 years ago

3 0

Answer:

i dont know im just doing this for the points

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At Farmer Jones Market, bananas cost $.80 per pound. At Farmer Garcia's

e-lub [12.9K]

divide $4.50 by 5 .......

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2 years ago

Someone please help . I have so much work due to wifi problems

quester [9]

Answer:

1. 24

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Step-by-step explanation:

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2 years ago

Se tiene un rectángulo cuya base mide el doble que su altura y su área es 12

irina [24]

Answer:

Part 1) The perimeter is $P=6\sqrt{6}\ cm$

Part 2) The diagonal is $d=\sqrt{30}\ cm$

Step-by-step explanation:

<u><em>The question in English is</em></u>

You have a rectangle whose base is twice the height and its area is 12

square centimeters. Calculate the perimeter of the rectangle and its diagonal

step 1

Find the dimensions of rectangle

we know that

The area of rectangle is equal to

$A=bh$

$A=12\ cm^2$

$bh=12$ ----> equation A

The base is twice the height

$b=2h$ ----> equation B

substitute equation B in equation A

$(2h)h=12\\2h^2=12\\h^2=6\\h=\sqrt{6}\ cm$

Find the value of b

$b=2\sqrt{6}\ cm$

step 2

Find the perimeter of rectangle

The perimeter is given by

$P=2(b+h)$

substitute

$P=2(2\sqrt{6}+\sqrt{6})\\P=6\sqrt{6}\ cm$

step 3

Find the diagonal of rectangle

Applying the Pythagorean Theorem

$d^2=b^2+h^2$

substitute

$d^2=(2\sqrt{6})^2+(\sqrt{6})^2$

$d^2=30$

$d=\sqrt{30}\ cm$

3 0

3 years ago

I have a 84% in class, there is a 25 point quiz worth 100 points, how what grade do I need to get to at least have an average gr

Thepotemich [5.8K]

At least about 20 points it can depend on the class but not really.

4 0

3 years ago

Read 2 more answers

The half-life of a certain substance is 20 years. How much of a 100 gram sample will be left after 20 years?

cluponka [151]

$\bf \textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &100\\ t=\textit{elapsed time}\dotfill &20\\ h=\textit{half-life}\dotfill &20 \end{cases} \\\\\\ A=100\left( \frac{1}{2} \right)^{\frac{20}{20}}\implies A=100\left( \frac{1}{2} \right)^1\implies A=50$

5 0

3 years ago

Read 2 more answers