All categories

4 years ago

9decimals with 3 decimal places when rounded to the nearest hundredth round to 4.56.

Mathematics

2 answers:

andrezito [222]4 years ago

7 0

Remember
≥5. then round up
<4 then round down

4.555
4.556
4.557
4.558
4.559
4.561
4.562
4.553
4.554

suter [353]4 years ago

6 0

? 123456.789 ?????

then round2(123456.789)

=123456.79

You might be interested in

Write the fraction as a percent. 1/10 please help

stiks02 [169]

Answer: the answer is 10%

Step-by-step explanation: 1/10. You have to get the denominator to 100 so, you would x10 the debonair. You do the same to the top and get 10/100. So, 10%

4 0

2 years ago

Read 2 more answers

Lilys car has a fuel efficiency of 8 liters per 100 kilometers.

WINSTONCH [101]

100 : 8 = 12.5

12.5 Km per liter is your answer

7 0

3 years ago

Read 2 more answers

The shape below is a cute with the length of 13cm. find the total surface area of the prism

olga_2 [115]

Answer:

The area is 1,014 cm^2

Step-by-step explanation:

Here, we want to find the total surface area of a cube with side length of 13 cm

what we shall do here is to apply the formula to get the total surface area

Mathematically, that will be

A = 6L^2

so we have

Area = 6 * 13^2

Area = 1,014 square cm

8 0

3 years ago

The velocity of a turtle is recorded at 1 minute intervals (in meters per second). Use the right-endpoint approximation to estim

aliina [53]

Answer:

The total distance that the turtle traveled during the 5 seconds recorded is $Distance \:traveled\approx 3.838\:\frac{m}{s}$

Step-by-step explanation:

To estimate distance traveled of an object moving in a straight line over a period of time, from discrete data on the velocity of the object, we use a Riemann Sum. If we have a table of values

$\left\begin{array}{ccccccc}time\:=\:t_i&t_0=0&t_1&t_2&...&t_n\\velocity\:=\:v(t_i)&v(t_0)&v(t_1)&v(t_2)&...&v(t_n)\end{array}\right$

where $\Delta t=t_i-t_{i-1}$ , then we can approximate the displacement on the interval $[t_{i-1},t_i]$ by $v(t_{i}) \times\Delta t$ .

Therefore the distance traveled of the object over the time interval $[0,t_n]$ can be approximated by

$Distance \:traveled\approx |v(t_1)|\Delta t+|v(t_2)|\Delta t+...+|v(t_n)|\Delta t$

This is the right endpoint approximation.

We are given a table of values for v(t)

$\left\begin{array}{cccccccc}t(sec)&0&1&2&3&4&5\\v(t)&0.078&0.83&0.75&0.98&0.853&0.425\end{array}\right$

Applying the right endpoint approximation formula we get,

$\Delta t = 1\sec$

$Distance \:traveled\approx |v(t_1)|\Delta t+|v(t_2)|\Delta t+|v(t_3)|\Delta t+|v(t_4)|\Delta t+|v(t_5)|\Delta t\\\\Distance \:traveled\approx 0.83(1)+0.75(1)+0.98(1)+0.853(1)+0.425(1)\\\\Distance \:traveled\approx 3.838\:\frac{m}{s}$

The total distance that the turtle traveled during the 5 seconds recorded is $Distance \:traveled\approx 3.838\:\frac{m}{s}$

4 0

3 years ago

Omar wrote 3 + ( 4 × 6 ) to represent the phrase "3 more then the product of 4 and 6." Did Omar need to use a grouping symbol? E

valentina_108 [34]

The order of operations is PEMDAS (parenthesis, exponents, multiplication/division, addition/subtraction). This means that you do multiplication before adding, so 3 + 4*6 is the same thing as 3 + (4*6). Because of this, Omar did not need to use a grouping symbol.

8 0

3 years ago

Read 2 more answers