Answer:
-13a
Step-by-step explanation:
You're basically just adding together two negatives
We know that,
In a right-angled triangle,
Hypotenuse ² = Base ² + Height ²
1 – 10 ² = 6 ² + X ²
Or, X ² = 10 ² – 6 ²
Or, X ² = 100 – 36
Or, X ² = 64
Or, X = √ 64
Or, X = 8 Units
2– X² = 7² + 3²
Or, X² = 49 + 9
Or, X² = 58
Or, X = √58
Or, X = 7.61 Units ( Approx )
3 – 15 ² = EF ² + 9
Or, EF² = 15 ² – 9 ²
Or, EF ² = 225 – 91
Or, EF ² = 134
Or, EF = √ 134
Or, EF = 11.6 Inches ( Approx)
.II} 1 – Here the length of the ladder will be the hypotenuse.
Hence, Hypotenuse = 13 Metre
.Now, The vertical wall will be the height.
Hence, Height = 12 Metre
Distance of the foot of the ladder to the wall will be the base.
Let base be B.
Now, Hypotenuse ² = Base ² + Height ²
Or, 13² = B² + 12²
Or, B² = 13² – 12²
Or, B² = 169 – 144
Or, B² = 25
Or, B = √25
Or, B = 5 Metre
Hence, the distance of the foot of the ladder from the wall is 5 metre apart.
Answer:
x = -14
Step-by-step explanation:
Answer:
The answer to your question is 10.7 units
Step-by-step explanation:
To solve this problem, just calculate the distance from the House to the Library, then the distance from the Library to the Post office and finally to the Post office to the house.
I hope this helps! Also, pls mark me as the brainliest!
AlSO IF YOU WANT THE STEP BY STEP EQUATION IT IS--->
dHL = \sqrt{(-2 + 3)^{2} + (-2 - 2)^{2}}
dHL = \sqrt{(1)^{2}+ (-4)^{2}}
dHL = \sqrt{17} = 4.1
dLP = \sqrt{(-2 -2)^{2} + (-2-2)^{2}}
dLP = \sqrt{(-4)^{2} + (-4)^{2}}
dLP = \sqrt{32} = 5.7
dPH = \sqrt{(2 + 3)^{2}+ (2 - 2)^{2}}
dPH = \sqrt{(5)^{2}+ (0)^{2}}
dPH = \sqrt{25}
dPH = 5
Minimum distance = 4.1 + 5.7 + 5
Minimum distance = 10.7
-----> PICTURE
Answer:
X=1550-10y
Step-by-step explanation:
X+10y=1550
Subtract 10y from each side
X+10y- 10y=1550-10y
X=1550-10y