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ELEN [110]
3 years ago
13

Simplify using Order of Operations. 12-3(10+23):9X(-2)

Mathematics
1 answer:
FromTheMoon [43]3 years ago
6 0
Parentheses ()
Exponents ^x
Multiplication/Division */
Add/Subtract +-

12-3(10+23):9x(-2)

(I don’t understand the “:” but it is right next to the / sign, so I will solve like that)
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Step-by-step explanation:

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The expression 6s^2 can be used to find the surface area of a cube whose side length is s. Find the
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Select all the points that are on the graph of the line y= -1/2x + 5
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3 years ago
Factor both quadratic expressions. (x 4 + 5x 2 - 36)(2x 2 + 9x - 5) = 0
Sonbull [250]

So focusing on x^4 + 5x^2 - 36, we will be completing the square. Firstly, what two terms have a product of -36x^4 and a sum of 5x^2? That would be 9x^2 and -4x^2. Replace 5x^2 with 9x^2 - 4x^2: x^4+9x^2-4x^2-36

Next, factor x^4 + 9x^2 and -4x^2 - 36 separately. Make sure that they have the same quantity inside of the parentheses: x^2(x^2+9)-4(x^2+9)

Now you can rewrite this as (x^2-4)(x^2+9) , however this is not completely factored. With (x^2 - 4), we are using the difference of squares, which is a^2-b^2=(a+b)(a-b) . Applying that here, we have (x+2)(x-2)(x^2+9) . x^4 + 5x^2 - 36 is completely factored.

Next, focusing now on 2x^2 + 9x - 5, we will also be completing the square. What two terms have a product of -10x^2 and a sum of 9x? That would be 10x and -x. Replace 9x with 10x - x: 2x^2+10x-x-5

Next, factor 2x^2 + 10x and -x - 5 separately. Make sure that they have the same quantity on the inside: 2x(x+5)-1(x+5)

Now you can rewrite the equation as (2x-1)(x+5) . 2x^2 + 9x - 5 is completely factored.

<h3><u>Putting it all together, your factored expression is (x+2)(x-2)(x^2+9)(2x-1)(x+5)=0</u></h3>
5 0
3 years ago
Y = -3x + 5 <br> 3x - 2y = -10
valentinak56 [21]

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(0,5)

Equation Form:

x = 0, y = 5

Step-by-step explanation:

hope i helped you :)

4 0
3 years ago
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