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tekilochka [14]
3 years ago
6

The length of the sides of a rectangle are 60 and 91 centimeters. The is the length of the diagonal?

Mathematics
2 answers:
vovikov84 [41]3 years ago
5 0

Answer:

109

Step-by-step explanation:

Given that the figure is a rectangle, then the diagonal and two sides will form a right triangle. This means that the Pythagorean theorem can be applied. The Pythagoren theorem states;

a^{2} + b^{2} = c^{2}

Where (a) and (b) are the legs or sides, and (c) is the hypothenuse also known as the diagonal or side opposite the right angle.

Substitute;

a^{2} + b^{2} = c^{2}\\\\60^{2} +91^{2} = c^{2}\\\\3600+8281=c^{2}\\\\11881=c^{2}\\\\109=c

Elena L [17]3 years ago
3 0

use Pythagoras

D=

d =  \sqrt{60 {  }^{2} }  + 91 {}^{2}

Diagonal =109 cm

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In ΔOPQ, o = 58 cm, q = 13 cm and ∠Q=52°. Find all possible values of ∠O, to the nearest degree.
PSYCHO15rus [73]

Answer:

There is no possible triangles

Step-by-step explanation:

\frac{\sin A}{a}=\frac{\sin B}{b}

a

sinA

​  

=  

b

sinB

​  

 

From the reference sheet (reciprocal version).

\frac{\sin O}{58}=\frac{\sin 52}{13}

58

sinO

​  

=  

13

sin52

​  

 

Plug in values.

\sin O=\frac{58\sin 52}{13}\approx 3.5157403

sinO=  

13

58sin52

​  

≈3.5157403O=\sin^{-1}(3.5157403)= \text{ERROR}

O=sin  

−1

(3.5157403)=ERROR

Sine cannot be greater than 1.

{No Possible Triangles}

No Possible Triangles

{}

{}

7 0
3 years ago
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