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son4ous [18]
4 years ago
15

If you were told to graph a function over the domain -1\leq x\leq 5−1≤x≤5 , identify what x-value we would start with and what x

-value we would stop at.
Mathematics
1 answer:
xxMikexx [17]4 years ago
8 0

Answer:

You would start with 00.-6 and stop a-5954

Step-by-step explanation:

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How many lines can be drawn through points J and K?
maria [59]

Answer:

<h2><u><em>1</em></u></h2>

Step-by-step explanation:

"Through any given two points X and Y, only one and only one  line can be drawn "

<u><em>so 1</em></u>

8 0
2 years ago
5/6-2/9=<br> pls help me
oee [108]

The answer is 11/18.

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4 0
3 years ago
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What is x in 7x-17=18
Evgen [1.6K]

Answer:

x=5

Step-by-step explanation:

7x-17=18

7x=18+17

7x=35

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5 0
3 years ago
The slope of the line below is 2. Which of the following is the point-slope form<br> of the line?
Allisa [31]
Point-slope form is y1 - y2 = m(x1 - x2). We know that the slope is 2, and we have a point of (1, -1). If we plug in our numbers, we will get y -(-1) = 2(x - 1). This gives us y + 1 = 2(x - 1). Therefore, the answer is B.
4 0
3 years ago
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PLEASE HELP<br> find the vertex of f(x)=x^2+2x+3 (make sure you show your work)
Solnce55 [7]

ANSWER

(-1,2)

EXPLANATION

The given quadratic expression is:

f(x) =  {x}^{2}  + 2x + 3

The coefficient of the quadratic term is already 1.

So we add and subtract the square of half the coefficient of x.

f(x) =  {x}^{2}  + 2x  + 1 - 1+ 3

We factor the first three terms to obtain

f(x) =(x  + 1)^{2}  + 2

This is now in the form:

f(x) =  a({x  -  h)}^{2}  +k

where (h,k) which is equal to (-1,2) is the vertex.

5 0
4 years ago
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