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2 years ago

How many lines can be drawn through points J and K?

Mathematics

1 answer:

maria [59]2 years ago

8 0

Answer:

Step-by-step explanation:

"Through any given two points X and Y, only one and only one line can be drawn "

so 1

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Start at 7 and subtract 3each time

Vlad1618 [11]

Answer:

7, 4, 1, -2, -5, -8, -11, -14, -17, -20

Step-by-step explanation:

8 0

3 years ago

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A grain silo is in the shape of a cylinder with a hemisphere top. They cylinder is 20 feet tall. The volume of the silo is 2106

andreyandreev [35.5K]

Answer:

The radius of the silo is 5.788 feet.

Step-by-step explanation:

Since the silo has the shape of a cylinder, then;

Volume of the silo = Volume of a cylinder = $\pi$ $r^{2}$ h

Where: r is the radius of the silo, and h is the height.

Given that: volume = 2106 cubic feet, and height = 20 feet.

Then,

2106 = $\frac{22}{7}$ x $r^{2}$ x 20

2106 = $\frac{440}{7}$ $r^{2}$

2106 x 7 = 440 $r^{2}$

14742 = 440 $r^{2}$

$r^{2}$ = $\frac{14742}{440}$

$r^{2}$ = 33.5045

⇒ r = $\sqrt{33.5045}$

= 5.78831

r = 5.788 feet

The radius of the silo is 5.788 feet.

5 0

3 years ago

Refer to the random sample of customer order totals with an average of $78.25 and a population standard deviation of $22.50. a.

zysi [14]

Answer:

a) $78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

b) $78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

c) For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

d) $ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

Step-by-step explanation:

Part a

For this case we have the following data given

$\bar X = 78.25$ represent the sample mean for the customer order totals

$\sigma =22.50$ represent the population deviation

$n= 40$ represent the sample size selected

The confidence level is 90% or 0.90 and the significance level would be $\alpha=0.1$ and $\alpha/2 = 0.05$ and the critical value from the normal standard distirbution would be given by:

$z_{\alpha/2}=1.64$

And the confidence interval is given by:

$\bar X -z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

Part b

The sample size is now n = 75, but the same confidence so the new interval would be:

$78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

Part c

For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

Part d

The margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

3 0

3 years ago

Choose the equation that best represents the general form of the following expression.

Nuetrik [128]

Here is how we get the equation that best represents the general form of the given expression above.
Since we have a fraction, what we are going to do in order to eliminate it is to multiply both sides by 2. So this gives us x^2 = 14x.
Move 14x, and the final form would be x^2 -14x = 0.
Hope this is the answer that you are looking for.

4 0

3 years ago

What is the value of 1-61? A. -6 B. -3 C. 0 D. 6

damaskus [11]

Answer:

D. 6

Step-by-step explanation:

| -6|

Absolute values means take the positive value

The positive value of -6 is +6

6 0

4 years ago

Read 2 more answers