can someone help me we out
We are given

Vertical asymptotes:
Firstly, we will factor numerator and denominator
we get

We can see that (x-3) is common in both numerator and denominator
so, we will only set x+3 to 0
and then we can find vertical asymptote


Hole:
We can see that (x-3) is common in both numerator and denominator
so, hole will be at x-3=0


Horizontal asymptote:
We can see that degree of numerator is 2
degree of denominator is also 2
for finding horizontal asymptote, we find ratio of leading coefficients of numerator and denominator
and we get


so, option-D............Answer
<h3>
Solution:</h3>
<u>A few tips...</u>
- Pythagoras theorem can ONLY be used in right triangles.
- Usually, the longest side is the hypotenuse.
Option A:
- 6² = 5² + 4²
- => 36 = 25 + 16
- => 36 ≠ 41
The <u>side lengths</u> given are <u>not possible</u> for a right triangle.
Option B:
- 50² = 40² + 30²
- => 2500 = 1600 + 900
- => 2500 = 2500
The <u>side lengths</u> given are <u>possible</u> for a right triangle.
Option C:
- 30² = 20² + 10²
- => 900 = 400 + 100
- => 900 ≠ 500
The <u>side lengths</u> given are <u>not possible</u> for a right triangle.
Option D:
- 4² = 3² + 2²
- => 16 = 9 + 4
- => 13 ≠ 16
The <u>side lengths</u> given are <u>not possible</u> for a right triangle.
<h3>In conclusion...</h3>
Answer:
1,4 and 1,0
Step-by-step explanation: if the x is the same then it is not a function.
Answer:
272
Step-by-step explanation:
you need to find the whole rectangle area (40 times 20)then subtract the cut off areas (6 times 32)