Answer:
![y=10000(1.015)^{12t}](https://tex.z-dn.net/?f=y%3D10000%281.015%29%5E%7B12t%7D)
option-B......Answer
Step-by-step explanation:
We are given
amount taken for loan =$10000
so, P=10000
annual interest rate =18%
r=0.18
now, we can use formula
![y=P(1+\frac{r}{n} )^{nt}](https://tex.z-dn.net/?f=y%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bnt%7D)
Since, it is compounded monthly
so, n=12
we can plug values
![y=10000(1+\frac{0.18}{12} )^{12t}](https://tex.z-dn.net/?f=y%3D10000%281%2B%5Cfrac%7B0.18%7D%7B12%7D%20%29%5E%7B12t%7D)
![y=10000(1.015)^{12t}](https://tex.z-dn.net/?f=y%3D10000%281.015%29%5E%7B12t%7D)
A. 53/100
B. 163/200
C. 53/10
D. 163/20
Those are the answers to the question.
Answer:
x=-5.25
y=13.75
Step-by-step explanation:
5x+3(-3x-2)=15
5x+-9x+-6=15
-4x+-6=15
-4x+-6+6=15+6
-4x=21