Ask question

Ask question

All categories

2 years ago

7

What is the 2nd equivalent fraction to 1/7?

2 answers:

aksik [14]2 years ago

7 0

Answer: 2/14; 3/21; 4/28

Step-by-step explanation:

Kryger [21]2 years ago

6 0

Hello there!

Equivalent fractions have the same value.

$\frac{1}{7} , \frac{2}{14}, \frac{3}{21} ...$ are equivalent fractions.

<h2>Therefore, the next equivalent fraction is $\frac{2}{14}$ .</h2>

Hope this helps you!

~Just a felicitous girlie

#HaveAMarvellousDay

$SilentNature :)$

You might be interested in

Combine like terms.

Vesna [10]

To combine these terms you would add up the a's and b's.
4a+b+a is the same as 4a+a+b. Anything without a constant in front has a value of 1. You have 4a's and you need to add another a. That equals 5a's. The b is left alone since you can only add like variables.
The answer would be C) 5a +b

5 0

3 years ago

Read 2 more answers

Can anyone please explain? Need some help :)

DedPeter [7]

Answer:

93.5 square units

Step-by-step explanation:

Diameter of the Circle = 12 Units

Therefore:

Radius of the Circle = 12/2 =6 Units

Since the hexagon is regular, it consists of 6 equilateral triangles of side length 6 units.

Area of the Hexagon = 6 X Area of one equilateral triangle

Area of an equilateral triangle of side length s = $\dfrac{\sqrt{3} }{4}s^2$

Side Length, s=6 Units

$\text{Therefore, the area of one equilateral triangle =}\dfrac{\sqrt{3} }{4}\times 6^2\\\\=9\sqrt{3} $ square units$

Area of the Hexagon

$= 6 X 9\sqrt{3} \\=93.5$ square units (to the nearest tenth)$

7 0

3 years ago

The difference of two numbers is 3 and the sum of their squares is 65. find the numbers.

Vitek1552 [10]

<span>The numbers are 4 and 7
j^2+k^2=65

4^2+7^2=65
16+49=65
65=65
hope i helped</span>

5 0

2 years ago

Read 2 more answers

Guys, Can you please help me with these questions

MakcuM [25]

Answer:

a) $w^{13} x^{5} y^{6}$

b) $\frac{x}{3y^{6} }$

Step-by-step explanation:

a) $(w^{2} xy^{3} )^{2}(w^{3}x )^{3}$

1. Distribute the second power (2) outside the first pair of parenthesis:

$(w^{2(2)} x^{2} y^{3(2)} )$

= $w^{4} x^{2} y^{6} (w^{3}x )^{3}$

2. Distribute the third power (3) outside the second pair of parenthesis:

$(w^{3(3)} x^{3} )$

= $w^{4} x^{2} y^{6} w^{9} x^{3}$

3. Combine like terms:

$w^{13} x^{5} y^{6}$

--------------------------------------------

b) $\frac{2x^{2} y^{5} }{6xy^{11} }$

1. Factor the number 6 (= 2 · 3):

$\frac{2x^{2} y^{5} }{2(3)xy^{11} }$

2. Cancel the common factor (2):

$\frac{x^{2} y^{5} }{3xy^{11} }$

3. Cancel out $xy^{5}$ in the numerator an denominator:

$\frac{x}{3y^{6} }$

hope this helps!

4 0

1 year ago

Match the expression with its factored form. 3x + 9

pogonyaev

Answer:

3(x +3)

Step-by-step explanation:

factored by grouping

3 0

2 years ago