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3 years ago

Evaluate the expression when y=5 and x=18 x-3y

Mathematics

2 answers:

Keith_Richards [23]3 years ago

6 0

Answer:

Step-by-step explanation:

Step 1: replace y for 5, and x for 18

x-3y

18-3(5)

Step 2: simplify.

18-15

dexar [7]3 years ago

4 0

Answer:

Step-by-step explanation:

18 - 3(5)= 18 -15= 3

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3 years ago

Write y= -3/4 x-6 in standard form using integers.

alexgriva [62]

Answer:

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y= -3/4 x-6

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4 years ago

What property could be used to solve x-3=-5

Phoenix [80]

Answer: additive inverse

Step-by-step explanation:

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3 years ago

What is the antiderivative of e^x^2?

ddd [48]

Answer: The antiderivative of $e^{x^{2}}$ is $\sqrt{\pi} \sqrt{e^{x^2}-1} +C$ .

Explanation:

$I=\int{e^{x^2}dx}\\I^2=\int{e^{x^2}dx}\int{e^{x^2}dx}$

Using dawson integral.

$I^2=\int{e^{x^2}dx}\int{e^{y^2}dy}$

$I^2=\int{\int{e^{x^2+y^2}dxdy}}$

Put $x^2+y^2=r^2$

$I^2=\int{\int{e^{r^2}rdrd\theta}}$

$\int_{0}^{2\pi}{d\theta}\int_{0}^{x}{re^{r^2}dr}$

Use substitution method and sunbstitute $r^2=t$ .

$\int_{0}^{2\pi}{d\theta}\int_{0}^{x^2}{\frac{1}{2}e^tdt}$

$I^2=\frac{1}{2}|\theta|_{0}^{2\pi}|e^t|_{0}^{x^2}\\I^2=\frac{1}{2}(2\pi)(e^{x^2}-1)\\I=\sqrt{\pi}\sqrt{e^{x^2}-1}$ .

Therefore, the antiderivative of $e^{x^{2}}$ is $\sqrt{\pi} \sqrt{e^{x^2}-1} +C$ .

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4 years ago