AC = AB + BC
= x + 2 + 7x - 3
= 8x - 1
QR = PR - PQ
= 13y + 25 - (8y + 5)
= 13y + 25 - 8y - 5
= 5y + 20
For the answer to the question above,
the answer is "<span>The student can have only one blood type, so the actual events are mutually exclusive. "</span>
<span>The probabilities are not mutually exclusive. Based on the group </span>
<span>P(Type O) = 9/20 = 45% or 0.45 </span>
<span>P(Type A) = 2/5 = 40% or 0.40 </span>
<span>P(Other) = 3/20 = 15% or 0.15
I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>
Answer:
![r = \sqrt[3]{\dfrac{3V}{4 \pi}}](https://tex.z-dn.net/?f=%20r%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B3V%7D%7B4%20%5Cpi%7D%7D%20)
Step-by-step explanation:
Answer:
90
Step-by-step explanation:
g(-10) = (-10)²+(-10)
= 100-10 = 90
