To determine the perimeter of the trapezoid, we just have to determine the distance between the pair of points which can be calculated through the equation,
d = √(x₂ - x₁)² + (y₂ - y₁)²
Substituting,
(1,4) and (-2,0) d = √(1 - -2)² + (4 - 0)² = 5
(-2,0) and (7,0) d= √(-2 - 7)² + (0 - 0)² = 9
(7,0) and (3,4) d = √(7 - 3)² + (0 - 4)² = 5.66
(3,4) and (1,4) d = √(3 - 1)² + (0 - 0)² = 2
The perimeter is the sum of the distances. Thus, the answer is 21.66.
Answer:
Step-by-step explanation:
N is between points M and O
MN = x
MO = 3x - 6
NO = x + 1
The way it reads MN + NO = MO
x + x + 1 = 3x - 6
2x + 1 = 3x - 6
2x - 2x +1 = 3x -2x - 6
1 = x - 6
1 + 6 = x
x = 7
MO = 3x - 6
MO = 3*7 - 6
MO = 21 - 6
MO = 15
For this case we have the following trigonometric relationship:
tan (theta) = C.O / C.A
Where,
theta: angle
C.O: opposite leg
C.A: adjoining catheto
Substituting values:
tan (25) = x / 5
Clearing x:
x = 5 * tan (25)
x = 2.33
Answer:
x = 2.3