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True [87]
3 years ago
8

I need to know the answer

Mathematics
2 answers:
julia-pushkina [17]3 years ago
5 0

Answer:

the answer is 68

are you girl??

hope it helps you

notka56 [123]3 years ago
3 0

Answer:

68

Step-by-step explanation:

its an isoscles triangle(angles of equal sides are equal)

i hope it helps..

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D=2 when C=17 they vary inversely what is d when c=68
kipiarov [429]
Well D=8.5C so divide 68 by 8.5 (answer is 8)
5 0
3 years ago
When a function is evaluated with a zero, what does it represent?
Gre4nikov [31]
We know that
the points where the graph of the function crosses the y-axis is when <span>a function is evaluated with a zero, these points represent the y-intercept of the function
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therefore
the answer is
Represent the y-intercept of the function
4 0
3 years ago
Your parents have a credit card with a balance of $3,287.90 at an interest rate of 14.5% APR. They pay $1,200.00 each month on t
aleksandrvk [35]

It will take them approximately 3 months to pay off the balance on the credit card

<h3 /><h3>First Month</h3>

To solve this problem, we need to find the interest on 3287.90 at 14.5%

for the first month, we would have

\frac{x}{3287.90}=\frac{14.5}{100}  \\x=476.74

Now we divide this by 12 to give the interest payable on the first month

\frac{476.75}{12}=39.73

So we have

(3287.90+39.73)-1200=2127.63

<h3>Second Month</h3>

We would do the same thing for the second month and it will give us

(\frac{x}{2127.63}=\frac{14.5}{100})/12\\\frac{308.506}{12}=25.71

For the second month, we have $25.71 as the interest payable

We can calculate how much would be left after the second month.

(2127.63+25.71)-1200=953.34

<h3 /><h3>Third Month</h3>

In the third month, since the balance remaining is less than the monthly payment schedule, we can assume they'd pay everything off which is 953.34.

From the calculations above, we can see that it'll take them 3 months to pay off the credit card balance.

The balance at the end of each month are;

  • $2,127.63
  • $953.34
  • $0

Learn more on APR here;

brainly.com/question/11686424

6 0
2 years ago
Simplify.<br> 3y - 4x + 6x - y<br> The simplified expression is???
Whitepunk [10]

Answer:

2y-4x+6x

=2y+2x

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
20 POINTS!! ASAP, PLS SHOW WORK TYY
Sergeeva-Olga [200]

Answer:

\sin(\theta)=-\sqrt5/5\text{ and } \csc(\theta)=-\sqrt5\\\cos(\theta)=2\sqrt5/5\text{ and } \sec(\theta)=\sqrt5/2\\\tan(\theta)=-1/2\text{ and } \cot(\theta)=-2

Step-by-step explanation:

First, let's determine which quadrant our angle θ lies in.

Remember ASTC, where:

Everything is positive in QI,

Only sine (and cosecant) is positive in QII,

Only tangent (and cotangent) is positive in QIII,

And only cosine (and secant) is positive in QIV.

Since our tangent is negative, and our cosine is positive, this means that our θ <em>must</em> be in QIV.

In QIV, sine is negative, tangent is negative, and cosine is positive.

With that, let's figure out the remaining trig ratios.

We know that:

\tan(\theta)=-1/2

Remember that tangent is the ratio of the opposite side to the adjacent side.

Let's figure out our hypotenuse using the Pythagorean Theorem:

a^2+b^2=c^2

Substitute 1 for a and 2 for b (we can ignore the negative since we're squaring anyways). This yields:

(1)^2+(2)^2=c^2

Square:

1+4=c^2

Add:

c^2=5

Take the square root:

c=\sqrt{5}

So, our square root is √5.

So, our three sides are: Opposite=1, Adjacent=2, and Hypotenuse=√5.

Sine and Cosecant:

Remember that:

\sin(\theta)=opp/hyp

Substitute 1 for the opposite and √5 for the hypotenuse. This yields:

\sin(\theta)=1/\sqrt5

Rationalize:

\sin(\theta)=\sqrt5/5

And since our angle is in QIV, we add a negative:

\sin(\theta)=-\sqrt5/5

Cosecant is simply the reciprocal of sine. So:

\csc(\theta)=-\sqrt5

Cosine and Secant:

Remember that:

\cos(\theta)=adj/hyp

Substitute 2 for the adjacent and √5 for the hypotenuse. This yields:

\cos(\theta)=2/\sqrt5

Rationalize:

\cos(\theta)=2\sqrt5/5

Since our angle is in QIV, cosine stays positive.

Secant is the reciprocal of cosine. So:

\sec(\theta)=\sqrt5/2

Tangent and Cotangent:

We were given that:

\tan(\theta)=-1/2

To find cotangent, flip:

\cot(\theta)=-2

And we're done!

7 0
3 years ago
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