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Lunna [17]
3 years ago
6

7 1/8 - 3 2/3 faction plz

Mathematics
2 answers:
VashaNatasha [74]3 years ago
8 0

Answer:

83/24

Step-by-step explanation:

Calculator.

hoa [83]3 years ago
8 0

Answer:

83/24 or 3 11/24

Step-by-step explanation:

Hope this helps

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Given the function g(x)=x^2+2x-5g(x)=x
dimaraw [331]

We have been given a function g(x)=x^2+2x-5. We are asked to find average rate of change of the function over the interval -6\leq x\leq 1.

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

For our given function b=1 and a=-6.

\text{Average rate of change}=\frac{g(1)-g(-6)}{1-(-6)}

g(1)=1^2+2(1)-5

g(1)=1+2-5

g(1)=-2

g(-6)=(-6)^2+2(-6)-5

g(-6)=36-12-5

g(-6)=19

\text{Average rate of change}=\frac{-2-19}{1+6}

\text{Average rate of change}=\frac{-21}{7}

\text{Average rate of change}=-3

Therefore, the average rate of change of the function is -3 over the interval -6\leq x\leq 1.

4 0
4 years ago
Question 5(Multiple Choice Worth 7 points)
kotegsom [21]

Answer:

  -∞ ; x = 3

Step-by-step explanation:

The graph tends toward -∞ as x approaches 3 from the left. Thus there is a vertical asymptote at x=3, the value of x that makes the denominator zero.

5 0
4 years ago
Which of the following sets is closed under multiplication?
andrezito [222]

B. {1,2}  because they are both whole numbers 0 is not one.

(Proof: Whole Numbers: This set is closed only under addition and multiplication. Integers: This set is closed only under addition, subtraction, and multiplication. Rational Numbers: This set is closed under addition, subtraction, multiplication, and division (with the exception of division by 0)"

7 0
3 years ago
Read 2 more answers
Last year, 9 companies decided to include their coupon in a local coupon pack. Each company had to print 589 copies of their cou
Bad White [126]

Answer:

5301

Step-by-step explanation:

There are 9 companies that needed to print 589 coupons each. Multiply the two numbers:

9 * 589 = 5301

7 0
3 years ago
In a ∆ABC , angle A + Angle B = 125° and Angle B + Angle C = 150° . Find all the angles of ∆ABC.​
mel-nik [20]

\large\underline{\sf{Solution-}}

Given that,

<em>In triangle ABC</em>

\purple{\rm :\longmapsto\:\angle A + \angle B = 125 \degree \: -  -  - (1) }

\purple{\rm :\longmapsto\:\angle B + \angle C = 150 \degree \:  -  -  - (2)}

We know,

Sum of all interior angles of a triangle is supplementary.

\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C = 180\degree }

<u>On adding equation (1) and (2), we get </u>

\purple{\rm :\longmapsto\:\angle A + \angle B + \angle B + \angle C = 125\degree  + 150 \degree \:}

\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C + \angle B = 275\degree \:}

\purple{\rm :\longmapsto\:180\degree + \angle B = 275\degree \:}

\purple{\rm :\longmapsto\:\angle B = 275\degree - 180\degree  \:}

\purple{\rm :\longmapsto\:\angle B = 95\degree  \:}

On substituting the value in equation (1) and (2), we get

\purple{\rm :\longmapsto\:\angle A + 95\degree  = 125\degree }

\purple{\rm :\longmapsto\:\angle A =  125\degree - 95\degree  }

\purple{\rm :\longmapsto\:\angle A =  30\degree  }

Also, from equation (2), we get

\purple{\rm :\longmapsto\:95\degree  + \angle C = 150\degree }

\purple{\rm :\longmapsto\:\angle C = 150\degree  - 95\degree }

\purple{\rm :\longmapsto\:\angle C = 55\degree }

Hence,

\begin{gathered}\begin{gathered}\bf\: \rm\implies \:\begin{cases} &\sf{\angle A = 30\degree }  \\ \\ &\sf{\angle B = 95\degree } \\ \\ &\sf{\angle C = 55\degree } \end{cases}\end{gathered}\end{gathered}

3 0
3 years ago
Read 2 more answers
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