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antiseptic1488 [7]
3 years ago
11

Given the function g(x)=x^2+2x-5g(x)=x

Mathematics
1 answer:
dimaraw [331]3 years ago
4 0

We have been given a function g(x)=x^2+2x-5. We are asked to find average rate of change of the function over the interval -6\leq x\leq 1.

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

For our given function b=1 and a=-6.

\text{Average rate of change}=\frac{g(1)-g(-6)}{1-(-6)}

g(1)=1^2+2(1)-5

g(1)=1+2-5

g(1)=-2

g(-6)=(-6)^2+2(-6)-5

g(-6)=36-12-5

g(-6)=19

\text{Average rate of change}=\frac{-2-19}{1+6}

\text{Average rate of change}=\frac{-21}{7}

\text{Average rate of change}=-3

Therefore, the average rate of change of the function is -3 over the interval -6\leq x\leq 1.

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The only true statement is line segment ED intersects line segment AB.

<h3>What is a transversal?</h3>

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learn more about transversal here :

brainly.com/question/17987539

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