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2 years ago

Given r=3 and a center of (3,5)? Find the equation of the circle in standard and general form.

Mathematics

1 answer:

alukav5142 [94]2 years ago

8 0

9514 1404 393

Answer:

(x -3)^2 +(y -5)^2 = 9
x^2 +y^2 -6x -10y +25 = 0

Step-by-step explanation:

The standard form equation for a circle of radius r and center (h, k) is ...

(x -h)^2 +(y -k)^2 = r^2

For radius 3 and center (3, 5), this is ...

(x -3)^2 +(y -5)^2 = 9 . . . . standard form equation

Expanding this and subtracting the constant on the right gives ...

x^2 -6x +9 +y^2 -10y +25 -9 = 0

x^2 +y^2 -6x -10y +25 = 0 . . . . general form equation

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