All categories

3 years ago

Given r=3 and a center of (3,5)? Find the equation of the circle in standard and general form.

Mathematics

1 answer:

alukav5142 [94]3 years ago

8 0

9514 1404 393

Answer:

(x -3)^2 +(y -5)^2 = 9
x^2 +y^2 -6x -10y +25 = 0

Step-by-step explanation:

The standard form equation for a circle of radius r and center (h, k) is ...

(x -h)^2 +(y -k)^2 = r^2

For radius 3 and center (3, 5), this is ...

(x -3)^2 +(y -5)^2 = 9 . . . . standard form equation

Expanding this and subtracting the constant on the right gives ...

x^2 -6x +9 +y^2 -10y +25 -9 = 0

x^2 +y^2 -6x -10y +25 = 0 . . . . general form equation

You might be interested in

Ed is doing a survey of popular colors for cars for a school report. He decides to take a sample by sitting near a busy intersec

Goryan [66]

17+25=42
21+9=30

12 more white and blue than silver and red

3 0

3 years ago

Find the value of X and the value of Y. <br> (10 POINTS)

Ganezh [65]

sin 45 = opp/hyp

sin 45 = 4 / y

y = 4/sin 45

y = 4 /((sqrt2)/2)=4* sqrt(2)

tan 45 =opp/adj

tan 45 = 4/(x-3)

1 = 4/(x-3)

x-3 = 4

x=7

3 0

3 years ago

What is 150/100 in decimal form and percent form

Andrews [41]

Decimal : 1.5
Percent : 150%

3 0

3 years ago

If f(x)=log2(x+4), what is f^-1(3)?

zalisa [80]

$f\left( x \right) =\log _{ 2 }{ \left( x+4 \right) } \\ \\ \log _{ 2 }{ \left( x+4 \right) } =y\\ \\ { 2 }^{ y }=x+4$

$\\ \\ x={ 2 }^{ y }-4\\ \\ \therefore \quad { f }^{ -1 }\left( x \right) ={ 2 }^{ x }-4\\ \\ \therefore \quad { f }^{ -1 }\left( 3 \right) ={ 2 }^{ 3 }-4=4$

3 0

4 years ago

Read 2 more answers

WILL MARK BRAINLIEST

slamgirl [31]

Answer:

down 6,right 4, rotate 180 degrees assuming we are starting from the blue heart.

Step-by-step explanation:

4 0

3 years ago