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zalisa [80]
2 years ago
13

Given r=3 and a center of (3,5)? Find the equation of the circle in standard and general form.

Mathematics
1 answer:
alukav5142 [94]2 years ago
8 0

9514 1404 393

Answer:

  • (x -3)^2 +(y -5)^2 = 9
  • x^2 +y^2 -6x -10y +25 = 0

Step-by-step explanation:

The standard form equation for a circle of radius r and center (h, k) is ...

  (x -h)^2 +(y -k)^2 = r^2

For radius 3 and center (3, 5), this is ...

  (x -3)^2 +(y -5)^2 = 9 . . . . standard form equation

Expanding this and subtracting the constant on the right gives ...

  x^2 -6x +9 +y^2 -10y +25 -9 = 0

  x^2 +y^2 -6x -10y +25 = 0 . . . . general form equation

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Anon25 [30]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
For each sequence, find the first 4 terms and the 10th term.<br> A) n+5<br> B)2n-1
snow_tiger [21]

Answer:

see explanation

Step-by-step explanation:

(a)

To find the first 4 terms substitute n = 1, 2, 3, 4 into the n th term formula.

a₁ = 1 + 5 = 6

a₂ = 2 + 5 = 7

a₃ = 3 + 5 = 8

a₄ = 4 + 5 = 9

For the 10 th term substitute n = 10, that is

a₁₀ = 10 + 5 = 15

The first 4 terms are 6, 7, 8, 9 and the 10 th term is 15

(b)

Substitute n = 1, 2, 3, 4 and 10 into the n th term formula

a₁ = 2(1) - 1 = 2 - 1 = 1

a₂ = 2(2) - 1 = 4 - 1 = 3

a₃ = 2(3) - 1 = 6 - 1 = 5

a₄ = 2(4) - 1 = 8 - 1 = 7

a₁₀ = 2(10) - 1 = 20 - 1 = 19

The first 4 terms are 1, 3, 5, 7 and the 10 th term is 19

5 0
3 years ago
15 = 3h-9<br> Please explain
Afina-wow [57]
The answer is h=15+9/3=8
6 0
3 years ago
Read 2 more answers
Solve this fraction:4\3+6\9-7\3,,,and simplified if it can simplify....
icang [17]
4/3+6/9-7/3=12/9+6/9-21/9=18/9-21/9= -3/9= -1/3
4 0
3 years ago
The formula for the area of a parallelogram is A = bh, where b is the base and h is the height. A parallelogram that is not draw
Bezzdna [24]

Answer:

Option 2)  2x3 – 6x2 – 14x + 24 square centimeters

Step-by-step explanation:

We know the Parallelogram Area is given by

A=bh      Eqn. (1)

where

b : is the base

h  : is the height

We are also given that the base is

b=2x^2+2x-6

and the height is

h=x-4

So we can plug these two expressions in Eqn. (1), simplify and find our Area equation as follow:

A=(2x^2+2x-6)(x-4)\\\\A=(2x^2)(x)+(2x)(x)-(6)(x)+(2x^2)(-4)+(2x)(-4)-(6)(-4)\\\\A=2x^3+2x^2-6x-8x^2-8x+24\\\\A=2x^3+2x^2-8x^2-6x-8x+24\\\\A=2x^3-6x^2-14x+24

Which matches Option 2. from the available ones.

3 0
3 years ago
Read 2 more answers
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