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Nuetrik [128]
3 years ago
9

Help please! 10+ points!! Include a diagram and solution :)

Mathematics
2 answers:
devlian [24]3 years ago
7 0

Answer:

brainiest?

Step-by-step explanation:

Readme [11.4K]3 years ago
7 0

Answer:

A lighthouse is observed by a ship�s office on watch at an angle of 42 degree to the path of the ship.

At the next sighting the lighthouse is observed at an angle of 90 degree to the path of the ship.

The distance travel between sightings is 1800 m .

To the nearest meter, how far away is the ship to the lighthouse at this second sighting?

:

This situation, forms a right triangle, we can use the tangent of 42 degrees

where

side adjacent = 1800 m

side opposite = distance (d) from the ship to the lighthouse when the angle is 90

:

tan(42) = d%2F1800

d = .9004 * 1800

d ~ 1621 meters from the ship to the light

Step-by-step explanation:

A lighthouse is observed by a ship�s office on watch at an angle of 42 degree to the path of the ship. At the next sighting the lighthouse is observed at an angle of 90 degree to the path of the ship. The distance travel between sightings is 1800 m .To the nearest meter, how far away is the ship to the lighthouse at this second sighting?

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Answer:

Step-by-step explanation:

for two angles x and y,

x and y are supplementary angles if they add up to 180°

i.e x + y = 180°

8 0
3 years ago
Karen was trying to factor 6x^2+10 She found that the greatest common factor of these terms was 2 and made an area model
Kay [80]
<h2>Explanation:</h2><h2></h2>

In this case we have the following expression:

6x^2+10

We know that Karen was trying to factor out this and she found that the greatest common factor of these terms was 2, in other words we can write this expression as:

2(3x^2+5)

An area model for this expression could be the area of a rectangle that has the following dimensions:

W=2 \\ \\ L=3x^2+5 \\ \\ \\ Where: \\ \\ W:width \\ \\ L:length

So the area model can be written as:

A=W\times L \\ \\ \boxed{A=2(3x^2+5)}

4 0
3 years ago
4. At Lilly's Bakery, the ideal weight of a loaf of bread is 24 ounces. By law, the actual weight can vary from
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It can be 25.5 to 22.5
4 0
3 years ago
A sample of 200 observations from the first population indicated that x1 is 170. A sample of 150 observations from the second po
igor_vitrenko [27]

Answer:

a) For this case the value of the significanceis \alpha=0.05 and \alpha/2 =0.025, we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

z_{\alpha/2} =1.96

If the calculated statistic |z_{calc}| >1.96 we can reject the null hypothesis at 5% of significance

b) Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8  

c)z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708    

d) Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

Step-by-step explanation:

Data given and notation    

X_{1}=170 represent the number of people with the characteristic 1

X_{2}=110 represent the number of people with the characteristic 2  

n_{1}=200 sample 1 selected  

n_{2}=150 sample 2 selected  

p_{1}=\frac{170}{200}=0.85 represent the proportion estimated for the sample 1  

p_{2}=\frac{110}{150}=0.733 represent the proportion estimated for the sample 2  

\hat p represent the pooled estimate of p

z would represent the statistic (variable of interest)    

p_v represent the value for the test (variable of interest)  

\alpha=0.05 significance level given  

Concepts and formulas to use    

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

We need to apply a z test to compare proportions, and the statistic is given by:    

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

a.State the decision rule.

For this case the value of the significanceis \alpha=0.05 and \alpha/2 =0.025, we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

z_{\alpha/2} =1.96

If the calculated statistic |z_{calc}| >1.96 we can reject the null hypothesis at 5% of significance

b. Compute the pooled proportion.

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8  

c. Compute the value of the test statistic.                                                                                              

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.    

Replacing in formula (1) the values obtained we got this:    

z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708    

d. What is your decision regarding the null hypothesis?

Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

5 0
3 years ago
Use a calculator to solve the following equation for θ on the interval [−90∘,90∘]. Sin(θ)=34
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The value of θ from the given equation is 48.59degrees

<h3>Trigonometry identity</h3>

Given the trigonometry function

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We are to find the value of theta that will make the expression true

Take the arcsin of both sides

arcsin Sin(θ)= arcsin(3/4)

θ = arcsin(3/4)

θ = 48.59

Hence the value of θ from the given equation is θ = 48.59 defense

Learn more on trig identity here:brainly.com/question/7331447

4 0
2 years ago
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