Answer:
75 times
Step-by-step explanation:
so 30 × 3 = 150
so, obviously you wouke do 75 × 3
this would equal 75
Check the picture below.
notice, the pairs in the Unit Circle are the (cosine , sine) pair, which are equivalent to (x , y) values in a cartesian plane.
2. Find the derivative of f (x) = 5x + 9 at x = 2.
A) 9
B) 5
C) 0
D) 10<span><span>
</span><span>f (x) = 5x + 9
</span><span>The first thing we should do in this case is to derive the function.
</span><span>We have then:
</span><span>f '(x) = 5
</span><span>We now evaluate the function for the value of x = 2.
</span><span>We have then:
</span><span> f '(2) = 5
</span><span>Answer:
</span><span> the derivative of f (x) = 5x + 9 at x = 2 is:
</span><span>B) 5
</span><span>3. Find the derivative of f (x) = 8 divided by x at x = -1.
</span><span>4
</span><span>0
</span><span>8
</span><span> -8
</span><span>f (x) = 8 / x
</span><span>The first thing we should do in this case is to derive the function.
</span><span>We have then:
</span><span>f '(x) = ((0 * x) - (1 * 8)) / (x ^ 2)
</span><span> Rewriting we have:
</span><span> f '(x) = -8 / (x ^ 2)
</span><span>We now evaluate the function for the value of x = -1.
</span><span> We have then:
</span><span>f '(- 1) = -8 / ((- 1) ^ 2)
</span><span>f '(- 1) = -8
</span><span>Answer:
</span><span>The derivative of f (x) = 8 divided by x at x = -1 is:
</span><span>-8
</span><span> 4. Find the derivative of f (x) = negative 11 divided by x at x = 9.
</span><span> A) 11 divided by 9
</span><span>B) 81 divided by 11
</span><span>C) 9 divided by 11
</span><span> D) 11 divided by 81
</span><span> f (x) = -11 / x
</span><span>The first thing we should do in this case is to derive the function.
</span><span> We have then:
</span><span>f '(x) = ((0 * x) - (1 * (- 11))) / (x ^ 2)
</span><span>Rewriting we have:
</span><span> f '(x) = 11 / (x ^ 2)
</span><span>We now evaluate the function for the value of x = 9.
</span><span>We have then:
</span><span> f '(9) = 11 / ((9) ^ 2)
</span><span> f '(9) = 11/81
</span><span>Answer:
</span><span>the derivative of f (x) = negative 11 divided by x at x = 9 is:
</span><span>D) 11 divided by 81
</span><span>5. The position of an object at time is given by s (t) = 3 - 4t. </span><span>Find the instantaneous velocity at t = 8 by finding the derivative.
</span><span>s (t) = 3 - 4t
</span><span>For this case, the first thing we must do is derive the given expression.
</span><span>We have then:
</span><span>s' (t) = - 4
</span><span>We evaluate now for t = 8
</span><span> s' (8) = - 4
</span><span>Answer:
</span><span> the instantaneous velocity at t = 8 by finding the derivative is:
</span><span>s' (8) = - 4</span></span>
The answer to the above equation is 3
Step-by-step explanation:
(a-b)³+(b-c)³+(c-a)³: (a-b)(b-c)(c-a)
Let us consider (a−b)= x, (b−c)= y and (c−a)= z.
Hence, It is obvious that:
x+y+z =0 ∵all the terms gets cancelled out
⇒We must remember the algebraic formula
x³+y³+z³−3xyz= (x+y+z) (x²+y²+z²-xy-xz-yz)
Since x+y+z=0 ⇒Whole “(x+y+z) (x²+y²+z²-xy-xz-yz)
” term becomes 0
x³+y³+z³−3xyz =0
Alternatively, x³+y³+z³= 3xyz
Now putting the value of x, y, z in the original equation
(a-b)³+(b-c)³+(c-a)³ can be written as 3(a-b)(b-c)(c-a) since (a−b)= x, (b−c)= y and (c−a)= z.
3(a-b)(b-c)(c-a): (a-b)(b-c)(c-a)
= 3 ∵Common factor (a-b)(b-c)(c-a) gets cancelled out
Answer to the above question is 3
Answer:
$390
Step-by-step explanation:
so he has $500
he took $40,which is $460
then he put in $30,$490
then he took away $100,$390
hopefully you understand