Hello there! Your answer would be 1/4.
So to start, count up the total number of sections, and the number of red sections. There are 16 sections total, and 4 of them are red.
This can give us the ratio 4/16.
But next we need to simplify. What is the biggest number that can be divided by both 4 and 16? 4. So, divide both 4 and 16 by 4 to get your simplified answer.
4÷4/16÷4
1/4
So, the ratio of red sections to total sections, in lowest terms is 1/4.
The answer is: <span>40,000(1.12)(1.10)
Or 4 more understanding: 12% of £40000
</span>1%= 400, therefore, 12%= 4800.
In January, the value was £44800.
10% of this is £448.
Add £448 to £44800, giving you £45, 248
The slope is 1 and the y intercept is 0
Answer:
- Library 2 charges more for each book loaned.
- Library 1 has a cheaper subscription fee.
Step-by-step explanation:
Based on the table, we can write the equation for the cost of borrowing from Library 2 using the two-point form of the equation of a line:
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
for (x1, y1) = (2, 15.50) and (x2, y2) = (8, 26) this equation becomes ...
y = (26 -15.50)/(8 -2)(x -2) +15.50 . . . . . fill in the values
y = (10.50/6)(x -2) +15.50 . . . . . . . . . . . . simplify a bit
y = 1.75x -3.50 +15.50 . . . . . . simplify more
In the above, we have x = number of books; y = cost. We can use "n" and "C" for those, respectively, as in the equation for Library 1. Then the monthly cost for Library 2 is ...
C = 12 + 1.75n . . . . . . . arranged to the same form as for Library 1
_____
Now, we can answer the questions.
Library 2 charges more for each book loaned. (1.75 vs 1.50 for Library 1)
Library 1 has a cheaper subscription fee. (10 vs 12 for Library 2)
_____
The numbers in the cost equations are ...
C = (subscription fee) + (cost per book loaned)·n
Fresh Foods
Range: 2-4
Mode: 2
Median: 3
Mean: 3
Best Groceries
Range: 1-7
Mode: 1 and 5
Median: 3.5
Mean: 3.5
Range is the lowest and highest number. Mode is the number that repeats the most. Median is the number in the middle. Mean is adding all the numbers together and dividing it by the number of numbers.
