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Anettt [7]
3 years ago
8

Is the Brainly.it a fake website??

Mathematics
1 answer:
Allushta [10]3 years ago
6 0

Answer:

nah

Step-by-step explanation:

it helps u with homework

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Using the piling method, which of the following can be constructed from polygons alone? check all that apply
zimovet [89]

Answer:

Prism, Pyramid not including vertex

Step-by-step explanation:

Apex

5 0
3 years ago
What number can be added to -13 to get a sum of 0
Korvikt [17]

Answer:

- 13 + 13 = 0

Step-by-step explanation:

8 0
3 years ago
I'm not really understanding how to set this up​
____ [38]

Answer: x = 21; y = 29.5

because 2y° and 59° are 2 opposing angles ⇒ 2y° = 59° ⇔ y = 29.5°

we also have: (3x - 4)° = 59° ( because of 2 parallel lines)

⇔ 3x = 59 + 4 = 63

⇔ x = 63/3 = 21

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP AGAIN WILL MARK BRAINLEST !!!!!
Archy [21]

Answer:

3

Step-by-step explanation:

g(-1) means what is g(x) when x=-1.

So find -1 under the column labeled x and then scroll directly to the right of that and you should see what g(-1).  It is 3

Here are my examples:

g(-8)=6

g(-5)=-2

g(-1)=3

g(0)=-5

7 0
4 years ago
Select the three number bonds that represent factor pairs of the number 56. CLEAR CHECK Number bond: 1 times 56 = 56. Number bon
Ray Of Light [21]

Answer:

The answer is -

Number bond: 1 times 56 = 56.

Number bond: 4 times 14 = 56.

Number bond: 7 times 8 = 56.

Step-by-step explanation:

We can define a factor pair as a set of two factors, which, when multiplied together, give a particular product.

For example -

5 and 6 are factors of 30 because 5×6 = 30

Now,

Given -

Number bond: 1 times 56 = 56.                         ...................(1)

Number bond: 4 times 14 = 56.                         ...................(2)

Number bond: 5 times 6 = 56.                         ...................(3)

Number bond: 7 times 8 = 56.                         ...................(4)

In equation (1)

1 times 56 = 1×56 = 56

⇒1 and 56 are the factor pairs of 56

Satisfies

In equation (2)

4 times 14 = 4×14 = 56

⇒4 and 14 are factor pairs of 56

Satisfies

In equation (3)

5 times 6 = 5×6 = 30 ≠ 56

⇒5 and 6 are not factor pairs of 56

Not Satisfies

In equation (4)

7 times 8 = 7×8 = 56

⇒7 and 8 are factor pairs of 56

Satisfies

∴ we get

The answer is -

Number bond: 1 times 56 = 56.

Number bond: 4 times 14 = 56.

Number bond: 7 times 8 = 56.

6 0
3 years ago
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