Answer:
RQS = 63
PQR = 126
Step-by-step explanation:
because QS is an angle bisector, PQS =SQR and PQR = 2*PQS.
Answer:
it is given
, angle 2
, angle 3
, converse alternate exterior angles theorem
Step-by-step explanation:
We know that angle 1 is congruent to angle 3 and that line l is parallel to line m because it is <u>given
</u>. We see that <u>
angle 2
</u> is congruent to <u>angle 3</u> by the alternate interior angles theorem. Therefore, angle 1 is congruent to angle 2 by the transitive property. So, we can conclude that lines p and q are parallel by the <u>
converse alternate exterior angles theorem
</u>.
The list of choices you included doesn't have any correct expressions on it.
-- If the rocket went straight up, and then dropped back at the same place
it was launched from, then it must have dropped straight down.
-- The route it followed on the way down was exactly the same as the
route it followed on the way up.
-- Since it reached a maximum height of 150-ft from the ground
and the route was straight, the length of the route was 150-ft.
-- (150-ft going up) plus (150-ft coming down) = 300-ft traveled all together.
Answer:
Three 60 degree angles would equal 180 degrees
Step-by-step explanation:
