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2 years ago

PLEASE HELP will give BRAIN

Mathematics

2 answers:

____ [38]2 years ago

7 0

Answer:

1. 15

2. 5

3. x/x

4. 189

Step-by-step explanation:

person above deserves brainlest

AysviL [449]2 years ago

5 0

Answer:

a) 15

b) 5

c) x/x

d) 189

hope this helps :)

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While exercising, a person’s recommended target heart rate is a function of age. The recommended number of beats per minute, y ,

Deffense [45]

Answer:

170 heart beat per minute.

Step-by-step explanation:

While exercising, a person’s recommended target heart rate is a function of age. The recommended number of beats per minute, y, is given by the function y = f(x) = − 0.85x + 187 where x represents a person’s age in years.

So, if my age is 21 years i.e. x = 21, then the number of recommended heart beats per minute for my age will be

y = f(21) = - 0.85(21) + 187 = - 17.85 + 187 = 169.15 ≈ 170. (Answer)

{Taking the larger integer value}

8 0

3 years ago

Find g'(t) for the function g(t) = 7/t^4

Alex17521 [72]

The differentiation of the function g(t) = 7/t⁴ will be equal to g¹(t)=-28/t⁵

<h3>What is differentiation?</h3>

The method of determining the derivative, or rate of change, of a function in mathematics.is termed as the differentiation.

Given that:-

$g(t)= \dfrac{7}{t^4}$

The derivative will be calculated as:-

$g'(t)=7 \dfrac{d}{dt}(t^{-4})\\\\\\g'(t)=7\times (-4t^{-5})\\\\\\g'(t)=\dfrac{-28}{t^5}$

Therefore the differentiation of the function g(t) = 7/t⁴ will be equal to g¹(t)=-28/t⁵

To know more about derivatives follow

brainly.com/question/954654

#SPJ1

3 0

2 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.