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antoniya [11.8K]
2 years ago
15

Please help!! markup and markdown word problems.

Mathematics
1 answer:
faust18 [17]2 years ago
3 0

Answer:

12, 1260

Step-by-step explanation:

Andrew paid $10 for a burger. The burger had a discount of 20%. This means that the $10 is 80% of the original price.

100% - 80% = 20%

To find the original price, you can multiply by 120%

10 * 120% = 12

Abby Matthews needs to mark up a refrigerator that costs $900 to 140% of the original price. To do this, you can directly multiply.

900 * 140% = 1260

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How do you do this? pls help !!!!!!!!
ValentinkaMS [17]

area is measured in "square" units. ... Area of a square = side times side. Since each side of a square is the same, it can simply be the length of one side squared. If a square has one side of 4 inches, the area would be 4 inches times 4 inches, or 16 square inches.

so you multiply the sides by each other.

8 0
3 years ago
Asking for help on this again because i reallu need it!!
shutvik [7]

Answer:

5. 5.8

6. 6

7. 6

Step-by-step explanation:

5. mean - add all values and divide by the number of values

2 + 4 + 4 + 5 + 5 + 5 + 6 + 6 + 6 + 6 + 7 + 9 + 10 = 75

mean = 75/13 = 5.8

6. median - middle value of values written in ascending order.

2 + 4 + 4 + 5 + 5 + 5 + 6 + 6 + 6 + 6 + 7 + 9 + 10

median = 6

7. mode - value that occurs most times

mode = 6

7 0
2 years ago
How do you subtract 42 minutes from 1 hour 25 minutes? explain what to do and why to do it.
ikadub [295]

Answer:

43

Step-by-step explanation:

you change the 1 hour into minute you and 60min to 25 minutes and then you subtract from 42 minutes to get the solution

8 0
3 years ago
A group of 3 adults and 5 children pay a total of $52 for movie tickets. A group of 2 adults and 4 children pay a total of $38 f
Ksivusya [100]
<span>x = child ticket price
y = adult ticket price 
5x+3y=52 the cost accounting for the first group.
3x+2y=38 the cost accounting for the second group.

Child price: 5$
Adult price: 9$</span>
3 0
3 years ago
Select the basic integration formula you can use to find the indefinite integral.
kondaur [170]

Answer:

\int \dfrac{du}{u}=\log|u|+C

\int u^n du=\dfrac{u^{n+1}}{n+1}+C

\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C

Step-by-step explanation:

a.

\int \dfrac{du}{u}=\log|u|+C    [\because \int \dfrac{dx}{x}=\log |x|+C]

b.

\int u^n du=\dfrac{u^{n+1}}{n+1}+C    [\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]

c.

\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C        [\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]

3 0
3 years ago
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