Exercise 3
3z-1/10^5
3z-1/100000
The correct answer for the question that is being presented above is this one: "<span>The missing digit is 3."</span>
The missing digit is represented by A ⇒ $1A2, where A represents a whole number from 0 to 9.
Try substituting any number from 0 to 9 for A (the middle digit or tens place) , then divide by 11 members.
<span>Option 2: A = 3 ⇒ $1 </span><span>3 </span>2
$ 132 ÷ 11 = $12
The only one-digit that gives a whole number quotient when it takes the place of tens digit in $1 __2 is<span> 3.</span><span> Because $ 132 ÷ 11 = $ 12. (Option 2)</span>
The missing digit is 3.
16
Explanation:
Okay so Jack started with 50 chocolates, and ended with 2.
The simple way to calculate it would be by realising that Jack only distributed 48 chocolates. We can find how many times 3 fits into 48 by dividing <span>48÷3=16</span>.
Using algebra, we substitute the value we want to find with x. Here what we want to find is the number of friends that were at Jack's party.
We know that he started with 50 chocolates, then distributed <span>3×</span> the number of friends present (which is x).
We write that down as <span>50−3x</span>
(It's minus because when chocolates are distributed, Jack is taking away from what he has.)
We know that after this, there were only 2 chocolates left, so it's
<span>50−3x=2</span>
Then we proceed by moving all the numbers to the right until only x is left:
<span>−3x=2−50</span>
<span>−3x=−48</span>
<span>x=<span><span>−48</span><span>−3</span></span></span>
<span>x=16</span>
Conclusion: The number of people that attended the party was 16
Answer:
soooooooo where's the rest of the question? LOL
Step-by-step explanation:
