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2 years ago

Please help me with this question!! Ill give BRAINLIEST!!

Mathematics

1 answer:

bazaltina [42]2 years ago

6 0

Answer:

Step-by-step explanation:

B is 4

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A welder works 8 hours a day at a rate of $25.00 per hour. The overtime rate is doubled the normal rate. On a particularday, the

Alborosie

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Step-by-step explanation:

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3 years ago

HELP PLEASE WRITE AWAY

AysviL [449]

The answer is B you divide 0.035 from 16 then subtract that number with 16 with 15.44 you divide it by 0.0425 and with the answer subtract 15.44 with it

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3 years ago

Please help me with this question.

insens350 [35]

Answer:

The correct answer is option C. 3/5= 0.60

Step-by-step explanation:

It is given that,the Venn diagram shows sports played by 10 students.

event A = The student plays basketball.

event B = The student plays soccer

<u>To find P(A|B))</u>

P(A) = 6

P(B) = 5

P(A ∩ B) = 3

We have P(A|B) = P(A ∩ B)/P(B)

= 3/5

= 0.6

Therefore the correct answer is option C. 3/5= 0.60

5 0

3 years ago

Please help this is past due

Rom4ik [11]

Answer:

See below.

Step-by-step explanation:

Alexi originally has $43 in his bank account and deposits $7 per week.

Week 1: $50

Week 2: $57

Week 3: $64

Week 4: $71

Week 5: $78

The pattern is that it increased $7 every week starting from $43.

A pattern rule would be: y = 7x + 43 where x represents the number of weeks.

7 0

2 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$