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vazorg [7]
3 years ago
8

Xkslgmvkdkskfnfjndngkckgkdks

Mathematics
1 answer:
NeX [460]3 years ago
7 0
X-3=66
x=69

69+41+(y-9)=180
110+y-9=180
101+y=180
y=79
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HELP ASAP!! WILL MARK BRAINLIST!! A LOT OF POINTSS
Fittoniya [83]

Answer:

Black = 84 cm^2

Blue = 84cm^2

gold = 60.2cm^2

1 ornament = 228.2 cm^2

100 ornaments - 22820 cm^2

Step-by-step explanation:

Black is a rectangle = A = l*w = 7*12 = 84 cm^2

We have 2 blue   This is a triangle  so multiply by 2  the area of a triangle

2 * A = 2(1/2 b*h) = bh = 12*7 = 84 cm^2

We have 2 gold   This is a triangle  so multiply by 2  the area of a triangle

2 * A = 2(1/2 b*h) = bh = 8.6*7 = 60.2 cm^2

The total surface area for one ornament is

84+84+60.2 = 228.2

100 ornaments

Multiply by 100

100 *228.2 = 22820 cm^2

8 0
3 years ago
Can you help me please?
SVETLANKA909090 [29]

Answer:

its 34

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Answer question 8,9 and 10 with full details.
Lelechka [254]

Answer:

See Explanation

Step-by-step explanation:

8. (1)

Area of trapezoid = 1/2(sum of || sides) *perpendicular distance

36 =1/2(x+ y) * 6

36 = ((x + y)*3

36/3 = x + y

12 = x + y

x + y = 12.... (1)

8(2)

It is given that:

x = 2y....(2)

From equations (1) & (2)

2y + y = 12

3y = 12

y = 12/3

y = 4

From equation (2)

x = 2y = 2*4

x = 8

9.

Area of square = 1 square m

Side of square = 1 m

Area of circle = 1 square m

\pi {r}^{2}  = 1 \\  {r}^{2}  =  \frac{1}{\pi}  \\ r =  \frac{1}{ \sqrt{\pi} }  \\ c = 2\pi \: r \\ c = 2\pi \times  \frac{1}{ \sqrt{\pi} }  \\ c = 2 \sqrt{\pi}  \\ c = 2 \sqrt{3.14}  \\ c = 2 \times 1.77200451 \\ c = 3.54400902 \\ c = 3.544 \\ difference = 3.544 - 1 = 2.544  \\difference \approx \: 2.54

4 0
3 years ago
[02.03]
SVEN [57.7K]

Answer:

2)  Equation 1 and Equation 2 have the same number of solutions.

Step-by-step explanation:

The two given equations are

1)  15x + 6 = 41                and                   2) 2x + 13 = 28

Solving both equations, we get

Solving (1) :   15x + 6 = 41 ⇒   15x  = 41 -  6 = 35

or, x = 35/15 ⇒ x = 7/3

Solving (2) :   2x + 13 = 28⇒   2x  = 28 -  13  = 15

or, x = 15/2 ⇒ x = 15/2

So, from above solutions we can say that Equation 1 and Equation 2 have the same number of UNIQUE solution.

6 0
3 years ago
5sin²α+3cos²α / 3sin²α-5cos²α = <br> if tgα=√2
fiasKO [112]
Tgα = tan(α) = sqrt(2)/1 = opposite/ adjacent
opposite = sqrt(2)
adjacent = 1
hypotenuse = sqrt(opposite^2 + adjacent^2)
= sqrt(sqrt(2)^2 + 1^2) = sqrt(3)

sin(α) = opposite/hypotenuse
= sqrt(2)/sqrt(3)

cos(α) = adjacent/hypotenuse
= 1/sqrt(3)

now we can calculate the value of
5sin²α+3cos²α / 3sin²α-5cos²α
... do the math
8 0
3 years ago
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