All categories

3 years ago

Please help properties of exponents

Mathematics

1 answer:

defon3 years ago

3 0

Answer:

Step-by-step explanation:

3. $c^{11}$ add exponents

4. $m^{60}$ multiply exponents

5. $x^{6} y^{18}$ distribute and multiply exponents

6. $-21 a^{47} *b$ multiply and then add exponents

7. $100 a^{14} b^{4} c^{12}$ distribute and multiply exponents

8. $n^{22}$ multiply and then add exponents

You might be interested in

Do the lengths 30,40,45 form a right triangle

aliya0001 [1]

Answer: No, It Don't.

5 0

3 years ago

Read 2 more answers

Fghtyuhkjk 1 sdfgdfhgfdgh

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

asjdyh aw8ehjw ashhh we8hdajs faedu wendlajsf a

3 0

3 years ago

Read 2 more answers

Find the minimum value of the function f(x)=x^2+5x-6

mash [69]

<h3><u>Explanation</u></h3>

Method 1 (Formula)

$\begin{cases}h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{2a} \end{cases}$

The vertex of Parabola is the maximum/minimum point depending on the value of a.

Find Vertex

<u>h-value</u>

$h = - \frac{5}{2(1)} \\ h = - \frac{5}{2}$

<u>k-value</u>

$k = \frac{4(1)( - 6) - {(5)}^{2} }{4(1)} \\ k = \frac{ - 24 - 25}{4} \\ k = \frac{ - 49}{4} \\ k = - \frac{49}{4}$

The minimum value is the value of k. Therefore the minimum value is - 49/4 at x = -5/2.

Method 2 (Derivative)

This is Calculus method. We simply differentiate the function then substitute y' = 0.

Differentiate Function

$f'(x) = 2 {x}^{2 - 1} + {5x}^{1 - 1} - 0 \\ f'(x) = 2x + 5$

Substitute f'(x) = 0

$0 = 2x + 5 \\ - 5 = 2x \\ - \frac{5}{2} = x$

Substitute x = -5/2 in the original equation.

$f(x) = {( - \frac{5}{2} )}^{2} + 5( - \frac{5}{2} ) - 6 \\ f(x) = \frac{25}{4} - \frac{25}{2} - 6 \\ f(x) = \frac{25}{4} - \frac{50}{4} - \frac{24}{4} \\ f(x) = \frac{25}{4} - \frac{74}{4} \\ f(x) = - \frac{49}{4}$

<h3><u>Answer</u><u /></h3>

<u> $\sf{the \: \: minimum \: \: value \: \: is \: \: - \frac{49}{4} \: \: at \: \: x = - \frac{5}{2} }$ </u>

4 0

3 years ago

uppose that we have a function with a constant amount of work done in initialization, a call to a log-linearsorting algorithm, a

White raven [17]

Answer:

The running time is quadratic (O(n²) )

Step-by-step explanation:

For the set up, we have a constant running time of C. The, a log-linearsorting is called, thus, its execution time, denoted by T(n), is O(n*log(n)). Then, we call n times a linear iteration, with a running time of an+b, for certain constants a and b, thus, the running time of the algorithm is

C + T(n) + n*(a*n+b) = an²+bn + T + C

Since T(n) is O(n*log(n)) and n² is asymptotically bigger than n*log(n), then the running time of the algorith is quadratic, therefore, it is O(n²).

7 0

3 years ago

What is the mean for this set of data? 14 62 35 38 58 46 62 A. 45 B. 46 C. 48 D. 62

garik1379 [7]

Answer:

A. 45

Step-by-step explanation:

3 0

3 years ago