What are the names for the parts of a right triangle are choose multiple :

Mathematics

2 answers:

rodikova [14]3 years ago

5 0

Answer:

If a and b are the lengths of the legs of a right triangle and c is the length of the ... So, for example, to square the number 5 you multiply 5 • 5, and to square the number ... In any right triangle, the area of the square drawn from the hypotenuse is ... triangle if you know the length of the triangle's other two sides, called the legs.

Nostrana [21]3 years ago

3 0

I’m trying to figure this out too

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A box was 3/4 full of marbles. The box fell on the floor. Thirty marbles fell out. This was 20% of the marbles in the box. How m

Hunter-Best [27]

Answer: -5.7

Step-by-step explanation:

3/4- 30= -29.25 and that was only 20% of the box that was dropped out of the box. -29.25 of 20% equals -5.85. 3/4 of 20% equals 0.15 subtract the 2 decimals and you will get -5.7

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3 years ago

Write an exponential model given the two points (6,130) and (7,220).

Katyanochek1 [597]

Answer:

y=90x−410

Step-by-step explanation:

in point-slope form, this would be...

y−130=90⋅(x−6)<-----

If you convert this to slope-intercept form this would be...

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3 years ago

Learning Task 1: Write the fraction of each shaded figure. Find the sum. Write your answer in your notebook.

Tresset [83]

<h3> Learning task 1</h3>

1. 3. 3. 1.

4. 2

2. 5. 4. 6.

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Step by step explanation:

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3 years ago

An electronic product contains 48 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the

BigorU [14]

Answer:

0.6173 = 61.73% probability that the product operates.

Step-by-step explanation:

For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$