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3 years ago

Evaluate the expression when x = 3 and y = 5.

Mathematics

1 answer:

MakcuM [25]3 years ago

3 0

Step-by-step explanation:

x = 3 and y = 5.

1: 2xy

2 x 3 x 5

=30

2: 6y divided by x

6 x 5 / 3

30/3

=10

3:4y- x

4 x 5 -3

20-3

=17

4:Y(to the power of two) -7x +2

5^2 -7 x 3 + 2

25-7x3+2

25-21+2

25-19

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the sum of two numbera is 122. the second number is 18 less than three times the first number. find the numbers. help please!

pishuonlain [190]

So you can write two equations
x + y = 122
y = 3*x - 18
by substitution:
x + (3x - 18) = 122
now you simplify:
4x - 18 = 122
4x = 140
x = 35
to find y, you can use the first equation
35 + y = 122
y = 87

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3 years ago

Determine the number of ice cubes in 32 glasses at rate of 20 ice cubes in 5 glasses

Georgia [21]

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Mariulka [41]

Perimeter of the ΔJKL is 48 cm

Solution:

Given $\triangle \mathrm{RST} \sim \Delta \mathrm{JKL}$ .

RS = 8 cm and JK = 12 cm

Perimeter of $\triangle R S T$ = 32 cm

Let us find the perimeter of $\Delta J K L$ .

<u>Property of similarity triangles:</u>

If two triangles are similar, then the ratio of their perimeters is equal to the ratio of their corresponding sides.

$$\frac{\text{Perimeter of}\ \triangle RST }{{\text{Perimeter of}\ \triangle JKL}} =\frac{RS}{JK}$

$$\Rightarrow\frac{32 }{{\text{Perimeter of}\ \triangle JKL}} =\frac{8}{12}$

Do cross multiplication.

$$\Rightarrow 32\times 12 ={8}\times {\text{Perimeter of}\ \triangle JKL}$

$$\Rightarrow 384 ={8}\times {\text{Perimeter of}\ \triangle JKL}$

Divide both sides of the equation by 8.

$$\Rightarrow 48 = {\text{Perimeter of}\ \triangle JKL}$

Hence perimeter of the ΔJKL is 48 cm.

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