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Nikolay [14]
3 years ago
7

100 POINTS PLZ HELP

Mathematics
2 answers:
crimeas [40]3 years ago
6 0

An ordered pair such as (3,-1), is a shorthand way of writing two variables, such as x = 3 and y = -1. The order of the numbers in the pair is important: x always comes before y.

An ordered pair is a composition of the x coordinate (abscissa) and the y coordinate (ordinate), having two values written in a fixed order within parentheses.

It helps to locate a point on the Cartesian plane for better visual comprehension.

The numeric values in an ordered pair can be integers or fractions.

Ordered Pair = (x,y)

Where, x = abscissa, the distance measure of a point from the primary axis “x”

And, y = ordinate, the distance measure of a point from the secondary axis “y”

In the Cartesian plane, we define a two-dimensional space with two perpendicular reference lines, namely x-axis and y-axis. The point where the two lines meet at “0” is the origin.

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST ☺️

Ymorist [56]3 years ago
6 0

Answer:

Please read below

Step-by-step explanation:

If Salesman A had one sale he would earn $1,365 because he makes $65 dollars per sale plus a weekly commission of $1,300. Salesman B would make $340 because he makes $300 dollars weekly and $40 per sale. Salesman C would make $900 dollars, because he makes no commission and gets only weekly pay. Altogether, they would make $2,605.

I am sorry I am so late but here is the answer in case anyone needs it!

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R= 120/48 or 2.5
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3 years ago
A storage tank contains a liquid radioactive element with a half-life of 96 years. It will be relatively safe for the contents t
PolarNik [594]

Answer:

The tank must remain intact for 1183 years.

Step-by-step explanation:

Exponential equation for decay:

The amount of a substance after t years is given by:

A(t) = A(0)e^{rt}

In which A(0) is the initial amount and r is the decay rate.

A storage tank contains a liquid radioactive element with a half-life of 96 years.

This means that A(96) = 0.5A(0), and we use this to find r.

A(t) = A(0)e^{rt}

0.5A(0) = A(0)e^{96r}

e^{96r} = 0.5

\ln{e^{96r}} = \ln{0.5}

96r = \ln{0.5}

r = \frac{\ln{0.5}}{96}

r = -0.0072

So

A(t) = A(0)e^{-0.0072t}

It will be relatively safe for the contents to leak from the tank when 0.02% of the radioactive element remains. How long must the tank remain intact for this storage procedure to be safe?

This is t for which A(t) = 0.0002A(0). So

A(t) = A(0)e^{-0.0072t}

0.0002A(0) = A(0)e^{-0.0072t}

e^{-0.0072t} = 0.0002

\ln{e^{-0.0072t}} = \ln{0.0002}

-0.0072t = \ln{0.0002}

t = -\frac{\ln{0.0002}}{0.0072}

t = 1183

The tank must remain intact for 1183 years.

5 0
3 years ago
Please help ASAP
Arisa [49]

Answer:

2 lessons per day for 27 days and 3 lessons a day for 4 days.

Step-by-step explanation:

66/31 = 2 4/31

Since 66 divided by 31 is 2 with remainder 4, you need to do 31 days of 2 lessons per day. To do the extra 4 lessons, do one more lesson per day for 4 of those days.

That results in:

2 lessons per day for 27 days and 3 lessons a day for 4 days.

Check:

2 lessons a day for 27 days = 2 * 27 = 54

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54 + 12 = 66

If you do 2 lessons a day for 27 days and 3 lessons a day for 4 days, you will do the 66 lessons.

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Answer:

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