One worker can finish a job in 9 hours, and another for 6 hours. The first worker started working at 7 am and the 2nd worker sta
rted one hour later. Find after how many hours the work will be finished if both workers did an equal amount of work.
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Answer:
Answers are below!
Step-by-step explanation:
(2 + g) (8)
= (2 + g) (8)
Add a 8 after the 2, and flip.
= (2)(8) + (g)(8)
= 16 + 8g
= 8g + 16
= (4) (8 + -5g)
Add another 4, then flip.
= (4) (8) + (4) (-5g)
= 32 − 20g
= - 20g + 32
−7 (5-n)
= (−7) (5 + -n)
Add another 7, then flip.
= (−7) (5) + (-7) (-n)
= −35 + 7n
= 7n - 35
Use the distributive property.
a (b + c) = ab + ac
a = 8
b = 2m
c = 1
= 8 × 2m + 8 × 1
Simplify, you get 16m + 8.
Use the distributive property.
a (b + c) = ab + ac
a = 6x
b = y
c = z
= 6xy - 6xz is the answer.
Apply minus plus rules.
Multiply the numbers.
3 x 2 = 6