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3 years ago

15

The perpendicular bisector of ABC intersect at point G and are shown in blue. Find BG

1 answer:

Bad White [126]3 years ago

4 0

Answer:

9

Step-by-step explanation:

I got it correct.

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Solve the right triangle

____ [38]

Answer:

C=5.831

a=30.964

b=59.036

Step-by-step explanation:

7 0

3 years ago

Two sides of an isosceles triangle measures 26 and 10. What is the possible value of the third side?

spin [16.1K]

The third side of the triangle is 26.

Explanation:

Given:

Two sides of the isosceles triangle are 26 and 10.

To Find:

The possible value of the third side

Solution:

Definition of Isosceles triangle:

An isosceles triangle is a triangle with (at least) two equal sides. Isosceles triangle has both two equal sides and two equal angles.

We also know the property of the triangle that

Sum of two sides of triangle > third side of the triangle

Case1. When third side is 10

Thee third side can’t be equal to 10 because it does not follow the rule of triangle

10+10>26………which is not possible

So the third side of the isosceles triangle is 26.

7 0

3 years ago

Macs hotel had 128 rooms, and 25% of the rooms in the hotel did not have an ocean view. Write an expression to find the total nu

GarryVolchara [31]

There are 103 hotel rooms that have ocean views.

3 0

3 years ago

The point P(7, −2) lies on the curve y = 2/(6 − x). (a) If Q is the point (x, 2/(6 − x)), use your calculator to find the slope

NARA [144]

Answer:

a) (i) $m = 2.22$ , (ii) $m = 2$ , (iii) $m = 2$ , (iv) $m = 2$ , (v) $m = 1.82$ , (vi) $m = 2$ , (vii) $m = 2$ , (viii) $m = 2$ ; b) $m \approx 2$ ; c) The equation of the tangent line to curve at P (7, -2) is $y = 2\cdot x + 12$ .

Step-by-step explanation:

a) The slope of the secant line PQ is represented by the following definition of slope:

$m = \frac{\Delta y}{\Delta x} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}$

(i) $x_{Q} = 6.9$ :

$y_{Q} =\frac{2}{6-6.9}$

$y_{Q} = -2.222$

$m = \frac{-2.222 + 2}{6.9-7}$

$m = 2.22$

(ii) $x_{Q} = 6.99$

$y_{Q} =\frac{2}{6-6.99}$

$y_{Q} = -2.020$

$m = \frac{-2.020 + 2}{6.99-7}$

$m = 2$

(iii) $x_{Q} = 6.999$

$y_{Q} =\frac{2}{6-6.999}$

$y_{Q} = -2.002$

$m = \frac{-2.002 + 2}{6.999-7}$

$m = 2$

(iv) $x_{Q} = 6.9999$

$y_{Q} =\frac{2}{6-6.9999}$

$y_{Q} = -2.0002$

$m = \frac{-2.0002 + 2}{6.9999-7}$

$m = 2$

(v) $x_{Q} = 7.1$

$y_{Q} =\frac{2}{6-7.1}$

$y_{Q} = -1.818$

$m = \frac{-1.818 + 2}{7.1-7}$

$m = 1.82$

(vi) $x_{Q} = 7.01$

$y_{Q} =\frac{2}{6-7.01}$

$y_{Q} = -1.980$

$m = \frac{-1.980 + 2}{7.01-7}$

$m = 2$

(vii) $x_{Q} = 7.001$

$y_{Q} =\frac{2}{6-7.001}$

$y_{Q} = -1.998$

$m = \frac{-1.998 + 2}{7.001-7}$

$m = 2$

(viii) $x_{Q} = 7.0001$

$y_{Q} =\frac{2}{6-7.0001}$

$y_{Q} = -1.9998$

$m = \frac{-1.9998 + 2}{7.0001-7}$

$m = 2$

b) The slope at P (7,-2) can be estimated by using the following average:

$m \approx \frac{f(6.9999)+f(7.0001)}{2}$

$m \approx \frac{2+2}{2}$

$m \approx 2$

The slope of the tangent line to the curve at P(7, -2) is 2.

c) The equation of the tangent line is a first-order polynomial with the following characteristics:

$y = m\cdot x + b$

Where:

$x$ - Independent variable.

$y$ - Depedent variable.

$m$ - Slope.

$b$ - x-Intercept.

The slope was found in point (b) (m = 2). Besides, the point of tangency (7,-2) is known and value of x-Intercept can be obtained after clearing the respective variable:

$-2 = 2 \cdot 7 + b$

$b = -2 + 14$

$b = 12$

The equation of the tangent line to curve at P (7, -2) is $y = 2\cdot x + 12$ .

7 0

3 years ago

Writing equations of lines

Valentin [98]

Step-by-step explanation:

Equation of straight line is y=mx+c

choose any two points on straight line

for me I choose:(-3,11) and (3,-1)

use these two points to find gradient,m.

m= (-1-11)/(3-(-3))

m= -2

now, y=-2x+c

choose any point on the straight line

I choose point (3,-1)

sub the point into the equation to find c

-1=-2(3)+c

c=5

equation: y=-2x+5

7 0

3 years ago