The solutions to the given system of equations are x = 4 and y = -9
<h3>Simultaneous linear equations</h3>
From the question, we are to determine the solutions to the given system of equations
The given system of equations are
-8x-4y=4 --------- (1)
-5x-y=-11 --------- (2)
Multiply equation (2) by 4
4 ×[-5x-y=-11 ]
-20x -4y = -44 -------- (3)
Now, subtract equation (3) from equation (1)
-8x -4y = 4 --------- (1)
-(-20x -4y = -44) -------- (3)
12x = 48
x = 48/12
x = 4
Substitute the value of x into equation (2)
-5x -y = -11
-5(4) -y = -11
-20 -y = -11
-y = -11 + 20
-y = 9
∴ y = -9
Hence, the solutions to the given system of equations are x = 4 and y = -9
Learn more on Simultaneous linear equations here: brainly.com/question/26310043
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The rule is minus 5.
So 20, 15, 10, 5, 0, -5
Answer:
18 pencils
Step-by-step explanation:
1/2 dozen:6
1 dozen:12
6+12=18
18 pencils
Answer:
We have the following equation: y = 36 - x. And we need to find which of the following points belong to the graph:
If any of the points belong to the equation, then the equality will be met.
Then:
7 = 36 - (-13)
7 = 36 + 13
7 = 49 ❌
1 = 36 - (-35)
1 = 71❌
5 = 36 - 11
5 = 25 ❌
3 = 36 - 27
3 = 9 ❌
None of the points belong to the graph. Therefore, all points are NOT on the grah of p(x) = 36 - x.
