Answer:
i think its b
Step-by-step explanation:
The answer is
5mn(KUASA DUA) -6gh(KUASA DUA) +2
If T and V are complementary angles, their sum is 90°.
V + T = 90°
48° + (2X+10)° = 90° . . . . . . . substitute given information
2X + 58 = 90 . . . . . . . . . . . . .. collect terms
2X = 32 . . . . . . . . . . . . . . . . .. subtract 58
X = 16 . . . . . . . . . . . . . . . . . .. divide by 2
The value of X is 16.
point-slope equation - y+3= -3/5( x+5)
slope-intercept form- y= -3/5x +b
Answer:
Step-by-step explanation:
Slope m = (-8-2)/(1+1)=-10/2 = -5
Perpendicular slope-1/m = -1/-5 = 1/5
Equation of a line with perpendicular slope is
y-y1=(-1/m)(x-x1)
y - 2 = (1/5)(x+1)
y =2 +(1/5)(x+1)
