I think it’s 6
I did 32-26 and got it
That’s all I got
The answer is B. It is a relation and also a function at the same time because it satisfies a specific domain
The graph of a quadratic function y = ax² is a VERTICAL parabola open upward or downward depending whether a (the coefficient of x) is positive or negative
The graph y² = ax or y = √ax is a HORIZONTAL parabola open to the right or to the left depending whether a (the coefficient of x) is positive or negative
The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
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You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
