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3 years ago

Can pls someone help with my homework pls I need help

Mathematics

1 answer:

lilavasa [31]3 years ago

8 0

Answer:

$\sin(m < q) = \frac{7}{9} \\ \sin(m < q) =(0.77777777778) \\ m < q = { \sin 0.77777777778}^{ - 1} \\ m < q = (51.05755873102)$

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The area of rectangular kitchen tile is 6x^2-8x-30. The width is 2x-6.

mrs_skeptik [129]

Answer:

L=6x^2-4x+5

P=12x^2-4x-2

Step-by-step explanation:

A=WL

So, we know the area is 6x^2-8x-30 and the width is 2x-6

Substitute

(6x^2-8x-30)=(2x-6)(L)

L=(6x^2-8x-30)/(2x-6

Divide

L=6x^2-4x+5

P=2L+2W

Substitute

P=2(6x^2-4x+5)+2(2x-6)

P=12×^2-8x+10+4x-12

Simplify

P=12x^2-4x-2

7 0

3 years ago

What is the probability of getting two heads and two tails in four flips of a fair coin?

jekas [21]

Number of combinations possible = 4! / 2! 2! = 6

Each of these has probability 1/2*1/2*1/2*1/2 = 1/16

Required probability = 6 * 1/16 = 3/8

3 0

3 years ago

Please help I'm having a small brain moment

ahrayia [7]

Answer:

Option 4: r ≥ 6

Step-by-step explanation:

5(6+3r) + 7 ≥ 127

30 + 15r + 7 ≥ 127

37 + 15r ≥ 127

15r ≥ 90

r ≥ 6

5 0

3 years ago

You have drawn a simple random sample of 36 college students, asking each student how much rent they pay per month. You obtain a

Karo-lina-s [1.5K]

Answer:

$573-1.690\frac{22}{\sqrt{36}}=566.8033$

$573+1.690\frac{22}{\sqrt{36}}=579.1967$

And the 90% confidence interval would be between [566.80 and 579.20]

Step-by-step explanation:

Information given

$\bar X=573$ represent the sample mean

$\mu$ population mean (variable of interest)

s=22 represent the sample standard deviation

n=36 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=36-1=35$

The Confidence level is 0.90 or 90%, the significance would be $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value for this case would be $t_{\alpha/2}=1.690$

And replacing we got:

$573-1.690\frac{22}{\sqrt{36}}=566.8033$

$573+1.690\frac{22}{\sqrt{36}}=579.1967$

And the 90% confidence interval would be between [566.8033 and 579.1967]

6 0

4 years ago

Someone please help... (needs work)

Gala2k [10]

............................

3 0

3 years ago