Answer:
Length = 13
Width = 7
Step-by-step explanation:
Given:
length = 2(width) - 1
Area of a Rectangle = lω = 91 cm²
Calculation:
Area of a Rectangle = lω = 91 cm²
(2ω-1)ω = 91
= 2ω²- ω - 91 = 0
=(2ω+13)(ω-7)=0
ω = -6.5 ω=7
length = 2(width) - 1
l=2(7) - 1
l = 13
Answer:
8x^5 + 12x^4 - 26^3 + 11x^2 + 27x - 42
Step-by-step explanation:
(2x^2 + 3x - 6)(4x^3 - x + 7)
8x^5 -2x^3 +14x^2 + 12x^4 - 3x^2 + 21x -24x^3 + 6x - 42
8x^5 + 12x^4 - 26^3 + 11x^2 + 27x - 42
It is important to notice firs of all that the train with no stop acceleration and them no stop acceleration would have a faster travel between stops. given this is safe to assume that there is a period during while the train is not accelerating nor decelerating. To find the time that is speed is constant
let's assume non-stop accelerating and decelerating and the time lost (subtraction of both) is the time the train had constant speed:
assuming same time accelerating a decelerating we have that the distance is
x = voT + 1/2aT^2 (initiial speed = 0) (0.25 miles = 1320 feets)
1320 = 1/2 (8)(T/2)^2
T/2 = 18.17 seg
T = 36.34 seg
time of constant speed
T = 41 -36.34 = 4.66 seg
maximum speed
v = v0 + aT (initial speed = 0)
v = 8(18.17) (time accelerating)
v = 145.36 feets/sec
distance at full speed
x = v*t
x = 145.36*4.66 = 677.38 feets
Solving for X it would be
X=-4-2y
Solving for Y it would be
Y=-2-x/2
