Answer:
c. x = -1/15
Step-by-step explanation:
5/2x - 1/3 = -1/2 [multiply the whole equation by 6 (lowest common denom)
15x - 2 = -3 [add 2 on both sides of equation
15x = -1 [divide both sides by 15 to isolate x]
x = -1/15
Answer:
3.2
Step-by-step explanation:
11.5 - 5.1 = 6.4
6.4 ÷ 2 = 3.2
Yeah it would be A. because x approaching infinity is to the right of the graph, and since there is a horizontal asymptote at -3 then its correct
Step-by-step explanation:
Hint : we will check for each option whether it is an experiment or not by using the concepts of probability first we will check then if a coin is tossed then it is an experiment or not ? then we will check that if a dice is rolled is it an experiment or not and then we will repeat the same process for choosing a marble from a jar
complete step by step answer and event is a set of outcomes of an experiment to which probability is assigned as take an example when we and I the possibility of 5 appearing on the die is an event if for tossing a coin we do not know the result when a coin is tossed in can give any result whether it will be a head or tails so this is an example for a random experiment if a six-sided dice will be rolled then we do not know what is about to come there result can be anything from 126 so it is also an example for random experiment choosing a marble from a jar is also an experiment because we are choosing one marble from the jar and experiment is a work in which a result can be anything hence option d is the correct option not probability is how likely something is about to happen when a coin is tossed there are two possibility outcomes heads or tails show the probability of an outcome 1
( number of ways it can happen )÷
( total number of outcomes)
so when a coin is tossed the total number of outcomes are to solve the probability of a current head is 1/2
Answer:
YET
Step-by-step explanation:
TO DECRYPT DKA USING THE CAESAR SHIFT CIPHER STARTING WITH 5 SHIFTS.
TO DO THIS DECRYPTION, WE'RE GOING TO LOOP THE ALPHABETS.
D = LOOPING THIS LETTER 5 TIMES, WE HAVE C - B - A - Z - Y.
SO, D IS DECRYPTED AS Y
GOING FURTHER, THE ENCRYPTION SHIFTS BY AN ADDITIONAL SPACE. THIS MEANS, IF THE FIRST "Y" WAS ENCRYPTED IN 5 SPACES TO GET D, AND AN ADDITIONAL SPACE WAS ADDED TO THE NEXT ALPHABET, IT BECOMES 6.
K IS THEN DECRYPTED AS
K = J - I - H - G - F - E
K IS DECRPYTED AS E
GOING FURTHER, THE NEXT WAS ENCRYPTED WITH AN ADDITIONAL SPACE EVEN MORE, SO, A IS DECRPYTED AS
A = Z - Y - X - W - V - U - T.
THUS, DKA IS DECRYPTED AS YET
