ΔACD is similar to ΔBCD by AA similarity theorem
AD/AC = BD/BC
x/5 = 4.2/6
6x = 21
x = 3.5
Hope this helps! ;)
Who is Wharton. I don’t get it is it a convo
The result is the perpendicular bisector of AB, perpendicular to the segment AB, and through its midpoint.