Given :
As a plane takes off it ascends at a 20 degree angle of elevation.
If the plane has been travelling at an average rate of 290 ft/s and continues to ascend at the same angle.
To Find :
How high is the plane after 10 seconds.
Solution :
Distance travelled by plane, D = 2900 ft.
Angle of elevation, Ф = 20°.
Height gained is given by :

H = 2900 × sin 20°
H = 991.86 ft.
Therefore, height of plane after 10 seconds is 991.86 ft.
Hence, this is the required solution.
answer: 1 over 165 step by step: #1 Evaluate the power 5 to the power of 1= 5 because any expression raised to the power of 1 if u asking what's is an expression the expression is five and together is 5 to the power of 1) #2 if a term like five doesn't have a exponent the exponent is 1) #3 remove the parathesis ) #4 subtract 1 and -2 u get 1 over 5 to the power of -4 and 5 to the power of negative four is 1 over 165) the second I don't know
Answer:
Angle 1 is 62°
Angle 2 is 45°
Angle 3 is 24°
Step-by-step explanation:
Answer: 30 inches
Step-by-step explanation:
Given:
ABC-tringle
BH= 8 in - height
S= 120 in^2
AC-?
Solution:
S=1/2ab
120in=1/2a*8in
120=4a
4a=120
a=30 in