Find the equation of the line that is perpendicular to 5x-6y=5, and passes through Point A (-1,1).
2 answers:
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Answer:
The equation of line in slop-intercept form is y = +
Step-by-step explanation:
Given as :
The slope of the a line = m =
The line is passes through points = 15 ,
<u>According to question</u>
Equation of line in slope - intercept form
y - = m × ( x -
)
Or, y - ( ) =
× ( x - 15 )
Or, y - ( ) =
× x - (
) × 15
Or, y - ( ) =
× x + 6
Or, y = × x + 6 -
Or, y = × x +
Or, y = × x +
So, The equation of line in slop-intercept form y = × x +
Hence, The equation of line in slop-intercept form is y = +
Answer