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3 years ago

How do you solve this math problem?

Mathematics

2 answers:

Phantasy [73]3 years ago

5 0

<span>How do you solve this math problem?

1-3/7=4/7</span>

FromTheMoon [43]3 years ago

4 0

You just do 1/1 then multiply that by 7 which would be 7/7. Then do 7/7 - 3/7 which would be 4/7 (which can not be simplified)

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Make p the subject of the relation A is equal to 1/2 ( p + b) h

Amanda [17]

Answer:

2A /h -b =p

If you need it with a common denominator

(2A -bh)/h = p

Step-by-step explanation:

A = 1/2 ( p+b)h

Multiply each side by 2

2A = ( p+b)h

Divide by h

2A/h = ( p+b)h/h

2A/h = ( p+b)

Subtract b

2A/h -b = p+b -b

2A /h -b =p

If you need it with a common denominator

(2A -bh)/h = p

3 0

3 years ago

A cylindrical jar has a radius of 5 inches and a height of 9 inches. The jar is filled with marbles that have a volume of 20 in3

Andreyy89

Answer:

a. Volume = π15.02 9.0=6361.73

b. I am very sorry, I don't know

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP!!

Lapatulllka [165]

Answer:

the total of straw are going to be 9 and there will be a 1/9 chances of getting the short straw. while each friend picks a straw the probability of getting a short straw is going to be higher because the amount of straws are going to be lessened.

4 0

3 years ago

Jenny's mom is 36 years old. If Jenny's great-grandmother is 90 years old, what percent of Jenny's mother's age is Jenny's great

Serjik [45]

Answer:

The age of Jenny's mom is 40 % of age of Jenny's great-grandmother. (Input: 40)

Step-by-step explanation:

The percentage needed is calculated by the following expression:

$x = \frac{n_{M}}{n_{G}}\times 100\,\%$

Where:

$x$ - Percentage of Jenny's mother with respect to Jenny's great-grandmother, measured in percentage.

$n_{M}$ - Age of Jenny's mother, measured in years.

$n_{G}$ - Age of Jenny's great-grandmother, measured in years.

If we know that $n_{M} = 36\,yr$ and $n_{G} = 90\,yr$ , the percentage is:

$x = \frac{36\,yr}{90\,yr} \times 100\,\%$

$x = 40\,\%$

The age of Jenny's mom is 40 % of age of Jenny's great-grandmother.

3 0

4 years ago

The electric cooperative needs to know the mean household usage of electricity by its non-commercial customers in kWh per day. A

vekshin1

Answer:

$15.7-2.58\frac{2.3}{\sqrt{1731}}=15.6$

$15.7+2.58\frac{2.3}{\sqrt{1731}}=15.8$

We are 99% confident that the true mean of electricity comsumption is between (15.6 and 15.8) kWh

Step-by-step explanation:

Information provided

$\bar X= 15.7$ represent the sample mean for the usage of electricity

$\mu$ population mean (variable of interest)

$\sigma= 2.3$ represent the population standard deviation

n=1731 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula if we know the population deviation:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level provided is 0.99 or 95%, the value of significance is $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

And replacing we got:

$15.7-2.58\frac{2.3}{\sqrt{1731}}=15.6$

$15.7+2.58\frac{2.3}{\sqrt{1731}}=15.8$

We are 99% confident that the true mean of electricity comsumption is between (15.6 and 15.8) kWh

7 0

4 years ago