Solve for t. d= -16t^2 + 12

Mathematics

1 answer:

IRINA_888 [86]2 years ago

3 0

Answer:

t=√d-12/4 and t=√-d-12/4, d≥12

Step-by-step explanation:

Hope this helps.

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Point M (-3, 5) is translated using this rule. (x, y) ----> (x - 1, y) What are the coordinates of M'?

Nuetrik [128]

Answer:

The coordinates of point M' are $M'(x,y) = (-4, 5)$ .

Step-by-step explanation:

According to the statement, we have the following translation rule:

$M'(x,y) = M(x,y) + (-1, 0)$ (1)

Where:

$M(x,y)$ - Original point.

$M'(x,y)$ - Translated point.

$(-1, 0)$ - Translation vector.

If we know that $M(x,y) = (-3, 5)$ , then the coordinates of the point M' are:

$M'(x,y) = (-3,5) + (-1,0)$

$M'(x,y) = (-4, 5)$

The coordinates of point M' are $M'(x,y) = (-4, 5)$ .

5 0

2 years ago

HELP ASAP

Naily [24]

Answer:

$y+4 = -\frac{1}{3} (x-1)$

Step-by-step explanation:

1) First, find the slope of the line. Use the slope formula $m = \frac{y_2-y_1}{x_2-x_1}$ to find the slope. Substitute the x and y values of the given points into the formula and solve:

$m = \frac{(-5)-(-4)}{(4)-(1)} \\m = \frac{-5+4}{4-1} \\m = \frac{-1}{3}$

So, the slope is $-\frac{1}{3}$ .

2) Use the point-slope formula $y-y_1 = m (x-x_1)$ to write the equation of the line in point-slope form. Substitute values for $m$ , $x_1$ , and $y_1$ into the formula.

Since $m$ represents the slope, substitute $-\frac{1}{3}$ in its place. Since $x_1$ and $y_1$ represent the x and y values of one point on the line, choose any one of the given points (it doesn't matter which one) and substitute the x and y values of it into the formula. (I chose (1,-4), as seen below). This gives the equation of the line in point-slope form.

$y-(-4) = -\frac{1}{3} (x-(1))\\y+4 = -\frac{1}{3} (x-1)$