Solve for t. d= -16t^2 + 12
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Hello!
Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.
Horizontal asymptotes are determined by:
1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.
2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.
3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.
To find the vertical asymptote:
2x² - 10 = 0
2(x² - 5) = 0
(x - √5)(x + √5) = 0
x = √5 and x = -√5
Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.
To find the horizontal asymptote:
If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.
Therefore, the horizontal asymptote of this function is y = 0.
Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0
