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castortr0y [4]
2 years ago
8

Trapezoid ABCD has an area of 525 cm squared. If height AB = 21 cm and BC = 37 cm, what is the measure of AD?​

Mathematics
1 answer:
Annette [7]2 years ago
8 0

Answer:

AD = 13

Step-by-step explanation:

Area of trapezoid ABCD

=  \frac{1}{2} (AB + AD) \times AB \\  \\  525=  \frac{1}{2} (37+ AD) \times21\\  \\  525 \times 2=  (37+ AD) \times21 \\  \\ 1050 = 21 \times 37 + 21AD \\  \\ 1050  = 777+ 21AD \\  \\  21AD  = 1050 - 777 \\  \\ 21AD  = 273 \\  \\ AD  =  \frac{273}{21}  \\  \\ AD  = 13

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