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3 years ago

How do you calculate the area of half a circle with a diameter of 10.2?

Mathematics

1 answer:

Helen [10]3 years ago

3 0

Answer:

5.2716 × 10-8^-8

Step-by-step explanation:

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I'LL GIVE BRAINLIEST !!! FASTER please explain how do you get the answer !

aliya0001 [1]

Answer:

Step-by-step explanation:

we have the angle of vertex in the isosceles triangle = 180-2*bottom coner= 180-65/2=50

3 angles in the equilateral triangle are equal to 60

we have 50 + 60 +h =the angle of PQR =180

h=70

7 0

3 years ago

Read 2 more answers

A container of motor oil is supposed to contain 1000 ml of oil. a quality control engineer is concerned about the variability of

svlad2 [7]

one hundred millimeters

p.s I am only nine

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3 years ago

Factorize this term: (a+b)raise to the power of 4 +4

zimovet [89]

Answer:

(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)

Step-by-step explanation:

Given :

(a + b)⁴⁺⁴

Solving :

(a + b)⁸
(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)

8 0

2 years ago

Can anyone help me find the coordinates (?,?) given that the shape is a parallelogram? (15 points)

xxTIMURxx [149]

The missing coordinates of the parallelogram is (m + h, n).

Solution:

Diagonals of the parallelogram bisect each other.

Solve using mid-point formula:

$$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right )$

Here $x_1=m, y_1=n, x_2=h, y_2=0$

$$=\left( \frac{m+h}{2}, \frac{n+0}{2}\right )$

$$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right )$

To find the missing coordinate:

Let the missing coordinates by x and y.

Here $x_1=0, y_1=0, x_2=x, y_2=y$

$$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{x}{2}, \frac{y}{2}\right )$

Now equate the x-coordinate.

$$ \frac{m+h}{2}=\frac{x}{2}$

Multiply by 2 on both sides of the equation, we get

m + h = x

x = m + h

Now equate the y-coordinate.

$$\frac{n}{2} = \frac{y}{2}$

Multiply by 2 on both sides of the equation, we get

n = y

y = n

Hence the missing coordinates of the parallelogram is (m + h, n).

5 0

3 years ago

How do you solve these problems?

Rzqust [24]

A)

$\bf log_4(x)=3\\\\
-----------------------------\\\\
log_{{ a}}{{ a}}^x\implies x\qquad \qquad 
\boxed{{{ a}}^{log_{{ a}}x}=x}\impliedby 
\begin{array}{llll}
\textit{we'll use this}\\
\textit{cancellation rule}
\end{array}\\\\
-----------------------------\\\\
4^{\cfrac{}{}log_4(x)}=4^3\implies x=4^3$

b)

$\bf 3^{2y}=81\qquad 
\begin{cases}
81=3\cdot 3\cdot 3\cdot 3\\
\qquad 3^4
\end{cases}\implies 3^{2y}=3^4\impliedby 
\begin{array}{llll}
\textit{same base}\\
exponents\\
must\ be\\
the\ same
\end{array}
\\\\\\
2y=4\implies y=\cfrac{4}{2}\implies y=2$

6 0

3 years ago