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KIM [24]
3 years ago
15

Check all the answers that represent the same level of precision. A. 100.6 B. 23.45 C. 1.1 D. 42

Mathematics
1 answer:
Bingel [31]3 years ago
7 0
A and D show the same level of precision because they both have numbers in the hundredth place.
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A cricket weighs 7/6 gram. A grasshopper weighs 0.76 gram. Which insect weighs more?
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Just divide 7 by 6 to convert the fraction to decimal form and then compare the two
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solomon has read 1/3 of his book. He finishes the book by reading the same amount eat night for 5 nights what fraction of the bo
Arada [10]
The answer is 2/3 for a fraction and the decimal number is 0.6666666667
8 0
3 years ago
Ace autos sell cars and pay sue each month as follows
Dima020 [189]

Sue's total pay of year will have three parts

1) Fixed Salary for 12 months

  one month salary = £1410

  so 12 month salary = £1410 x 12 = £16920

2) 26% of total profit

   Total cost to the company- £473,500

   Total income for the company - £549,000

   Profit =  Total income for the company - Total cost to the company

             =  £549,000 - £473,500 = £75500

    Sues income from profit = 26% of £75500 = (26 × 75500)/100 = £19630

3) Bonus if Sue sells at least 16 cars

   Given number of months when sue solds atleast 16 cars = 4

   So bonus income = 4 × 390 = £1560

Adding the three above parts

Sue's total pay for the year = £16920 + £19630 + £1560 = £38110




   


 


7 0
3 years ago
The volume of a rectangular box is 330 cubic inches. The length on one side of the top is 11 inches, and the height of the box i
Fiesta28 [93]

Answer: 110 square inches.

Step-by-step explanation:

The volume of a rectangular box would be:

V=length*width*height

In this case, we know the volume, the length and the height, and we don't know the width, so we're going to isolate it:

width=\frac{V}{length*height}

Substituting the data:

width=\frac{330}{11*3} =10in

This width is also the width of the top of the box, so the area of the top would be:

A=length*width\\A=11*10\\A=110in^{2}

5 0
3 years ago
Under a certain transformation T, AA'BC' is the image of AABC. The perimeter of AA'B'C' is twice the perimeter of ABC. What kind
Anika [276]

The dimensions of the image are twice the dimensions of the preimage,

which indicates that the transformation is a dilation.

  • The transformation <em>T</em> is; <u>a dilation transformation with a scale factor of 2, D₂</u>

Reasons:

The transformation applied to ΔABC = T

The image of ΔABC following the transformation, T = ΔA'B'C'

The perimeter of ΔA'B'C' = Twice the perimeter of ΔABC

Therefore, we have;

A'B' + B'C' + A'C' = 2 × (AB + BC + AC)

Which gives

A'B' + B'C' + A'C' = 2·AB + 2·BC + 2·AC

By similar triangles, we have the ratio of corresponding sides as follows;

\displaystyle \frac{AB}{A'B'}  = \frac{BC}{B'C'} = \mathbf{ \frac{AC}{A'C'}}

Which gives;

\displaystyle \frac{AB}{A'B'}  = \frac{AB}{2 \cdot AB} = \frac{1}{2}

A'B' = 2·AB

Therefore;

  • Triangle ΔA'B'C' is twice the dimension of triangle ΔABC, and <em>T</em> is <u>a dilation transformation with a scale factor of 2, D₂</u>

Learn more about dilation transformation here:

brainly.com/question/2458912

3 0
2 years ago
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