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Vilka [71]
3 years ago
7

How many solutions does the system of equations below have? y=-62 – 7 y=-62 – 7

Mathematics
1 answer:
aleksklad [387]3 years ago
3 0
The answer is 2 i think
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In a recent flu epidemic, the number of flu cases increased by 40% each week. There were 3,000 flu cases during the first week o
Alborosie

Answer:

2880

Step-by-step explanation:

The total number of people affected by flu during  the 2nd and 3rd week of January,  1200 + 1680  = 2880        

5 0
3 years ago
Pablo has completed 44 deliveries so far this week. He needs to make 55 deliveries for the week. What
Dennis_Churaev [7]

Answer:

<h2>80%</h2>

Step-by-step explanation:

step one:

completed delivery = 44

total delivery to be made= 55

Step two

Required is the percentage completed

the formula is

=completed/total*100

=44/55*100

=0.8*100

=80%

Hence  Pablo has completed 80% of the deliveries so far

3 0
3 years ago
Given F(x) = V(3x – 12) + 2, what is the range in set notation?
iogann1982 [59]

Answer:

(-∞,∞)

Step-by-step explanation:

6 0
3 years ago
Find the output (y) of the function y=6x+4 if the input (x) is 2
Dmitry_Shevchenko [17]

Answer:

f(2) = 16

or

y = 16

Step-by-step explanation:

Step 1: Write out function

y = 6x + 4

Step 2: Define variable for problem

<em>x</em> = 2

Step 3: Plug into function f(x)

f(2) = 6(2) + 4

f(2) = 12 + 4

f(2) = 16

Step 4: Change f(2) to y

y = 16

6 0
3 years ago
Which second-degree polynomial function has a leading coefficient of –1 and root 5 with multiplicity 2?
PIT_PIT [208]
A second degree polynomial function has the general form:

                  \displaystyle{f(x)=ax^2+bx+c, where a\neq0.

The leading coefficient is a, so we have a=-1.

5 is a double root means that :

i) f(5)=0,
ii) the discriminant D is 0, where D=b^2-4ac.

Substituting x=5, we have

                                        f(5)=a(5)^2+b(5)+c,

and since f(5)=0, and a is -1 we have:

                                          0=-25+5b+c
thus c=25-5b.


By ii) \displaystyle{b^2-4ac=0.

Substituting a with -1 and c with 25-5b we have:
                                     
          \displaystyle{b^2-4ac=0
          \displaystyle{b^2-4(-1)(25-5b)=0
          \displaystyle{b^2+4(25-5b)=0
          \displaystyle{b^2-20b+100=0
          \displaystyle{(b-10)^2=0
          \displaystyle{b=10 


Finally we find c: c=25-5b=25-50=-25

Thus the function is        \displaystyle{f(x)=-x^2+10x-25


Remark: It is also possible to solve the problem by considering the form

f(x)=-1(x-5)^2 directly.

In general, if a quadratic function has leading coefficient a, and has a root r of multiplicity 2, then its form is f(x)=a(x-r)^2
5 0
3 years ago
Read 2 more answers
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