Answer: Option a.
Step-by-step explanation:
Make the denominator equal to zero and solve for x:
Factor the quadratic equation. Find two number whose sum is -1 and whose product is -2. Then:
Then, as you can see the value x=2 makes the denominator equal to zero and the division by zero does not exist. Therefore you can conclude that the function shown in the problem is not defined at x=2
The answer is the option a.
<span>Let r(x,y) = (x, y, 9 - x^2 - y^2)
So, dr/dx x dr/dy = (2x, 2y, 1)
So, integral(S) F * dS
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx
= 28/5 + 40/9 - 1/4
= 1763/180 </span>
Answer:
70.7
Step-by-step explanation:
a2 +b2 = c2
50^2 + 50^2 = c2
c2 = 2500+2500
c = 
= 70.7
I hope im right!
Answer:
2 answers available depending on paranthesis
Step-by-step explanation:
5√2-4√2/√2 = 5√2 - 4
if there is a parenthesis like
(5√2 - 4√2)/√2 = 1√2/√2 =1
Answer:
I think is is 5.4
Step-by-step explanation:
what I did is divided the problem
