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Genrish500 [490]
3 years ago
9

Hpw to find exponential decay equation of radioaxtive subsrance

Mathematics
1 answer:
max2010maxim [7]3 years ago
5 0
I believe you are referring to the half-life formula, which is used to calculate the half-life (when the substance drops to half of its original amount) of radioactive substances.  The equation is as follows: A = P(.5)^{t/h}

<em>A</em> is the remaining amount
<em>P</em> is the initial amount
<em>t</em> is the time that has passed
<em>h</em> is the half-life of the substance

When plugging values into the equation, make sure that <em>t </em>and <em>h </em>are both measured in the same unit (e.g. <em>t </em>days and <em>h </em>days), as well as <em>A </em>and <em>P</em>.
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ASAP HELP HIGH POINTS <br> find the value of x.
Westkost [7]

Answer:

x ≈ 4.2 (nearest tenth)

Step-by-step explanation:

The chord of length 4 is the base of an isosceles triangle with height of 3.7 and sides equal to the radius (x).

An isosceles triangle comprises two right triangles, each with:

  • base = 2 units
  • height = 3.7 units
  • hypotenuse = x units

Therefore, to find x use Pythagoras' Theorem:  a² + b² = c²

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

⇒ a² + b² = c²

⇒ 2² + 3.7² = x²

⇒ x² = 17.69

⇒ x = √(17.69)

⇒ x = 4.2 (nearest tenth)

7 0
2 years ago
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Write a trinomial expression in standard form that has a degree of 5
rewona [7]

\text{We need to find a trinomial expression in standard form with degree 5.}\\&#10;\\&#10;\text{we know that a trinomial expression is an expression which consists}\\&#10;\text{three terms in it.}\\&#10;\\&#10;\text{also given that the degree of the trinomial is 5, so the highest exponent}\\&#10;\text{appear in the trinomial would be 5.}\\

\text{so if we write a trinomial expression in standard form with degree 5,}\\&#10;\text{the first term must be of the form }x^5.\\&#10;\\&#10;\text{next two terms can be any smaller exponent term or any constant.}\\&#10;\\&#10;\text{thus one such trinomial expression with degree 5 is: }\\&#10;\\&#10;x^5-3x^2+2

3 0
3 years ago
Solve this equation: 2s + s + 12 = 132.<br> a. s = 9<br> B. s = –30<br> C. s = 120<br> D. s = 40
madam [21]
The equation given in the question is
2s + s + 12 = 132
3s + 12 = 132
3s = 132 - 12
3s = 120
s = 120/3
   = 40
From the above deduction we can see that the value of the unknown variable comes out to be exactly 40. This is possible because there is a single unknown variable and a single equation to get the value of the variable from. So the correct option among all the options given in the question is option "D".
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3 years ago
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belka [17]

Answer:

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2 years ago
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I need help with these questions
Lunna [17]

Answer:

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Step-by-step explanation:

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